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alexira [117]
3 years ago
15

According to Egyptian artifacts, how early was the concept of the square root known?

Mathematics
2 answers:
sasho [114]3 years ago
6 0

Answer:

1650 a. C

Step-by-step explanation:

Square roots are mathematical expressions that arose when posing various geometric problems such as the diagonal length of a square. The Papyrus of Ahmes dated around 1650 a. C., which copies older texts, shows how the Egyptians extracted square roots.

kolbaska11 [484]3 years ago
3 0
The answer for your question is 1850 BCE 
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What is the area of rectangle RSTU? Show step by step!
pickupchik [31]

Step-by-step explanation:

We only know 1 side, and that is the width of 4. We only have the diagonals at our side. Half of the diagonal is 5. As a result, the diagonal is 10. I want you to imagine a triangle that has a base of 4 and a hypotenuse of 10. Use the Pythagorean Theorem to find b, or the height.

a² + b² = c²

4² + b² = 10²

16 + b² = 100

100 - 16 = 84

b² = 84

b = √84

b ≈ 9.165

Now we know the length of the rectangle, which is about 9.165. Multiply that by 4 to get the area.

9.165 * 4

36 + 0.4 + 0.24 + 0.020

36.4 + 0.24 + 0.02

36.64 + 0.02

36.66 u²

The area of rectangle RSTU is about 36.66 units squared.

8 0
2 years ago
Please help me brainiest is award
tester [92]

Answer:

-3 >-5

5>-4

Step-by-step explanation:

Negative 3 is closer to zero so that statement is true. Also it's obvious 5 is greater than negative 4

hope this helps. Please mark me brainiest          

7 0
3 years ago
Read 2 more answers
8(y+4)-2(y-1)=70-3y <br> solve for y
nirvana33 [79]

Answer:

y = 4

Step-by-step explanation:

8(y + 4) - 2(y - 1) = 70 - 3y ← distribute parenthesis and simplify left side

8y + 32 - 2y + 2 = 70 - 3y

6y + 34 = 70 - 3y ( add 3y to both sides )

9y + 34 = 70 ( subtract 34 from both sides )

9y = 36 ( divide both sides by 9 )

y = 4

6 0
1 year ago
If 4 divides a^2-3b^2, then at least one of the integers a and b is even.
OleMash [197]

Answer:

Step-by-step explanation:

Suppose, on the contrary, a and b are both odd integers, that is:

a=2n+1\\\\b=2m+1\\\\

m and n being some integers numbers.

This way you have to:

a^{2}-3b^{2}=(2n+1)^2-3(2m+1)^2=(4n^2+4n+1)-3(4m^2+4m+1)\\\\a^{2}-3b^{2}=4(n^2-3m^2+n-3m)-2=4(n(n+1)-3m(m+1))-2

The last expression cannot be divisible by 4 since 2 is not divisible by 4. The previous conclusion leads to a contradiction, which was generated from the assumption that a and b were both odd integers. In conclusion, at least one of the two a and b should be an even integer

3 0
3 years ago
What is 25% of 86?<br> thanks subscibe to
aliina [53]
25% is one fourth, so divide 86 by four
the answer is 21.5
8 0
3 years ago
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