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2 years ago

15

Think about the process On the weekends, Paul jogs 9/10 mile. On the weekdays, Paul jogs 5/10 mile. Which expression shows how m

any more miles Paul jogs on the weekends than on a weekday?

2 answers:

avanturin [10]2 years ago

8 0

Paul jogs 4/tenth mile more on the weekend

Vadim26 [7]2 years ago

5 0

4/tenth a mile that Paul jogs

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Which answer best describes the solution to the equation

german

Let's check
3m - 9 = 9+3m
collect like terms
3m -3m = 9 + 9
0m = 18
which is not possible, so it will not have any solutions

7 0

3 years ago

Read 2 more answers

Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo

nlexa [21]

Given:

Equation of line $7x-4y=-12$ .

To find:

The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

$7x-4y+12=0$

Slope of line is

$\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{7}{(-4)}$

$m_1=\dfrac{7}{4}$

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

$m_1m_2=-1$

$m_2=-\dfrac{1}{m_1}$

$m_2=-\dfrac{4}{7}$ $[\because m_1=\dfrac{7}{4}]$

Now, the slope of perpendicular line is $m_2=\dfrac{4}{7}$ and it goes through (-21,2). So, the equation of line is

$y-y_1=m_2(x-x_1)$

$y-2=-\dfrac{4}{7}(x-(-21))$

$y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)$

$y-2=-\dfrac{4}{7}x-12$

$y=-\dfrac{4}{7}x-12+2$

$y=-\dfrac{4}{7}x-10$

Therefore, the required equation in slope intercept form is $y=-\dfrac{4}{7}x-10$ .

7 0

3 years ago

The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C

DedPeter [7]

Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68

4 0

2 years ago

Gary is 3 years older than twice the age of His sister Elena which shows an equation for this situation

Lynna [10]

Answer: G = 2E + 3

<u>Step-by-step explanation:</u>

Let E represent Elena's age.

Then Gary(G) is two times Elena(E) plus 3 --> G = 2E + 3

8 0

3 years ago

Find the sample space for the experiment.

Bingel [31]

Answer:

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

Step-by-step explanation:

The sample space of an experiment is a set of all the possible values that satisfies that experiment.

The five supervisors are A, B, C, D and E.

Two are to selected.

The number of ways to select 2 supervisors from 5 is: ${5\choose 2}=\frac{5!}{2!(5-2)!} =\frac{5!}{2!\times 3!} = 10$

The sample space will consist of 10 combinations.

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

5 0

3 years ago