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krek1111 [17]
3 years ago
15

Think about the process On the weekends, Paul jogs 9/10 mile. On the weekdays, Paul jogs 5/10 mile. Which expression shows how m

any more miles Paul jogs on the weekends than on a weekday?
Mathematics
2 answers:
avanturin [10]3 years ago
8 0
Paul jogs 4/tenth mile more on the weekend
Vadim26 [7]3 years ago
5 0
4/tenth a mile that Paul jogs
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Calculate 10% of 80. show work
Setler [38]

Answer:

8

Step-by-step explanation:

Solution for What is 10 percent of 80:

10 percent * 80 =

( 10:100)* 80 =

( 10* 80):100 =

800:100 = 8

4 0
3 years ago
Select all the irrational numbers
sammy [17]

Answer:

what are the irrational numbers? and also, irrational numbers are never-ending decimals that have no pattern, such as pi; 3.141592653589793238426433832795028841971693993751058209749445923078164 0628620899862803482534211706

Step-by-step explanation:

irrational numbers cannot be written in fraction form

7 0
4 years ago
Please help!!!
monitta

(i) The measures of the angles are m ∠ TCM = m ∠ TCQ = m ∠ CMQ = 90°.

(ii) The lengths of sides CM and CQ are 2 cm and 2√2 cm, respectively.

(iii) The angle between the <em>side</em> face and the base is equal to θ = cos⁻¹ (2 / MT) and the angle between the <em>slant</em> edge and the base is θ = cos⁻¹ [2√2 / √(4 + MT²)].

<h3>How to analyze a right pyramid</h3>

In this problem we have a <em>right</em> pyramid as line segment TC is perpendicular to the base PQRS, which means that any line coplanar with PQRS is perpendicular to line segment TC. i) the measures of the angles are m ∠ TCM = m ∠ TCQ = 90°.

Besides, the base PQRS is a square, which is equivalent to four right triangles with angles 45° - 45° - 90° and each triangle can be divided into two <em>right</em> triangles. Hence, the measure of the angle CMQ is 90°.

ii) The length of the sides can be found by the 45-45-90 theorem, which states that the length of the hypotenuse is √2 times the length of any of the legs:

CQ = (√2 / 2) · PQ

CQ = (√2 / 2) · (4 cm)

CQ = 2√2 cm

CM = (√2 / 2) · (2 √2 cm)

CM = 2 cm

iii)  The angle between the <em>side</em> face, one of them contains the <em>line</em> segment MT and the base can be found by the following <em>inverse trigonometric</em> relation: (value of the pyramid height is missing)

θ = cos⁻¹ (CM / MT)

θ = cos⁻¹ (2 / MT)            (1)

Similarly, the angle between the <em>slant</em> edge and the base is found by Pythagorean theorem and <em>inverse trigonometric</em> relation: (value of the pyramid height is missing)

θ = cos⁻¹ (CQ / TQ)

θ = cos⁻¹ [2√2 / √(QM² + MT²)]

θ = cos⁻¹ [2√2 / √(4 + MT²)]          (2)

To learn more on pyramids: brainly.com/question/17615619

#SPJ1

5 0
2 years ago
Geometry math question
Veseljchak [2.6K]
Use my photo to see the work and answers! Hope this helped :)

3 0
4 years ago
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Simplify to create an equivalent expression 2 - 4 * 5 p + 1
ahrayia [7]

2 - 4 * 5p + 1

Simplified, this equation looks like this:

4 * 5p = 20p

2 - 1 = 1

20p + 1 is the simplified form of this equation.

8 0
4 years ago
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