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Alex_Xolod [135]
4 years ago
11

What is 1/100 of 605

Mathematics
2 answers:
pshichka [43]4 years ago
5 0
\frac{1}{100} , 605 =  \frac{121}{20}

Nice days.........
viktelen [127]4 years ago
4 0
The answer will be 6.05
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Can someone help please ? Thanks I’m advance
Pani-rosa [81]

Answer:

f(-3) = 16

Step-by-step explanation:

Given:

f(x) = 2x² + x + 1

Required:

f(-3)

Solution:

Substitute x = -3 into f(x) = 2x² + x + 1

f(-3) = 2(-3)² + (-3) + 1

f(-3) = 2*9 - 3 + 1

f(-3) = 18 - 3 + 1

f(-3) = 16

6 0
3 years ago
Complete the square x^2-10=16<br><br>​
Hatshy [7]

Answer:

(x - 5)² = 41

Step-by-step explanation:

* Lets revise the completing square form

- the form x² ± bx + c is a completing square if it can be put in the form

 (x ± h)² , where b = 2h and c = h²

# The completing square is x² ± bx + c = (x ± h)²

# Remember c must be positive because it is = h²

* Lets use this form to solve the problem

∵ x² - 10x = 16

- Lets equate 2h by -10

∵ 2h = -10 ⇒ divide both sides by 2

∴ h = -5

∴ h² = (-5)² = 25

∵ c = h²

∴ c = 25

- The completing square is x² - 10x + 25

∵ The equation is x² - 10x = 16

- We will add 25 and subtract 25 to the equation to make the

 completing square without change the terms of the equation

∴ x² - 10x + 25 - 25 = 16

∴ (x² - 10x + 25) - 25 = 16 ⇒ add 25 to both sides

∴ (x² - 10x + 25) = 41

* Use the rule of the completing square above

- Let (x² - 10x + 25) = (x - 5)²

∴ (x - 5)² = 41

3 0
3 years ago
Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.
julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

f(x,y)=4x^2+6y^2

Let g(x,y)=x^2+y^2=1

We have to find the extreme values  of the given function

\nabla f(x,y)

\nabla g(x,y)=

Using Lagrange multipliers

\nabla f(x,y)=\lambda \nabla g(x,y)

f_x=\lambda g_x

8x=\lambda 2x

Possible value x=0 or \lambda=4

If x=0 then substitute the value in g(x,y)

Then, we get y=\pm 1

f_y=\lambda g_y

12y=\lambda 2y

If \lambda=4 and substitute in the equation

Then , we  get possible value of y=0

When y=0 substitute in g(x,y) then we get

x=\pm 1

Hence, function has possible  extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

f(0,1)=6

f(0,-1)=6

f(1,0)=4

f(-1,0)=4

Therefore, the maximum value of f  on the circlex^2+y^2=1  is f(0,\pm1)=6 and minimum value of f(\pm1,0)=4

7 0
3 years ago
Which value is equivalent to 83⋅87
inna [77]

I'm confused can you edit your question and then ask it again

8 0
3 years ago
Is 10xyz3 a monomial binomial or trinomial
nexus9112 [7]
Trinomial: there are 3 variables
8 0
3 years ago
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