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Alex_Xolod [135]
3 years ago
11

What is 1/100 of 605

Mathematics
2 answers:
pshichka [43]3 years ago
5 0
\frac{1}{100} , 605 =  \frac{121}{20}

Nice days.........
viktelen [127]3 years ago
4 0
The answer will be 6.05
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Charlotte pays $24 for 3 yards of landscaping fabric and 6 yards of chicken wire. Kami pays $30 for 6 yards of landscaping fabri
vlabodo [156]

Answer: the price of 1 yard of chicken wire is $2

Step-by-step explanation:

Let x represent the cost of one yard of landscaping fabric.

Let y represent the cost of one yard of chicken wire.

Charlotte pays $24 for 3 yards of landscaping fabric and 6 yards of chicken wire. This means that

3x + 6y = 24 - - - - - - - - - - 1

Kami pays $30 for 6 yards of landscaping fabric and 3 yards of chicken wire. This means that

6x + 3y = 30 - - - - - - - - -2

Multiplying equation 1 by 6 and equation 2 by 3, it becomes

18x + 36y = 144

18x + 9y = 90

Subtracting

27y = 54

y = 54/27 = 2

Substituting y = 2 into equation 1, it becomes

3x + 6×2 = 24

3x = 24 - 12 = 12

x = 12/3 = 4

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scZoUnD [109]

Answer:

All of the above

Step-by-step explanation:

   Grants. Colleges, states, and the federal government give out grants, which don't need to be repaid.

   Ask the college for more money.

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   Apply for private scholarships.

   Take out loans.

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WILL MARK BRAINLEST HELPP ME
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Step-by-step explanation:

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The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
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