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Tcecarenko [31]
2 years ago
13

You are about to install a new USB camera on your Linux system and you realize that there is no device special file available fo

r your device. What command can you use on the system to create a new device special file
Computers and Technology
1 answer:
Nonamiya [84]2 years ago
3 0

Answer:

mknod

Explanation:

When the user wants to configure a camera device on his Linux computer and the user recognizes that his device does not have a device-specific file. Thus, the user could use the mknod command on his computer to set up an equipment file because it is the command that is used to create a fresh file and these files are not the same as the normal file.

So, the following answer is correct according to the following scenario.

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Which scenario is most likely due to an everyday problem rather than a
tester [92]

The scenario is most likely due to an everyday problem rather than cultural difference among people collaborating online is option D. A team member's bandwidth is limited, and the video feed keeps freezing.

<h3>What is collaborating online?</h3>

Online collaboration is known to be a term that connote the use the internet as well as other forms of online tools to be able to work together on some work or project.

Note that it is one that is done Instead of a person sitting in a physical office space, the online collaboration gives room for employees to be able to work together from different locations and tech by accessing the virtual work environments as well as other shared online workspaces.

Therefore, The scenario is most likely due to an everyday problem rather than cultural difference among people collaborating online is option D. A team member's bandwidth is limited, and the video feed keeps freezing.

Learn more about collaborating online from

brainly.com/question/514815

#SPJ1

6 0
1 year ago
Use the arr field and mystery () method below.
kolezko [41]

Answer:

The sum of all positive even values in arr

Explanation:

We have an array named arr holding int values

Inside the method mystery:

Two variables s1 and s2 are initialized as 0

A for loop is created iterating through the arr array. Inside the loop:

num is set to the ith position of the arr (num will hold the each value in arr)

Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).

When the loop is done, the value of s1 and s2 is printed.

As you can see, s1 holds the sum of positive even values in the arr

7 0
2 years ago
Which of the following correctly describes the syntax of an If statement?
Ber [7]

if(Expression to be tested) {

code to execute

} else if(Expression to be tested) {

code to execute

}


you can have as many else ifs as you want. But that's what it looks like.

8 0
3 years ago
For what reason can security risks never be fully eliminated?​
raketka [301]

Answer:

A vulnerability level of ZERO can never be obtained since all countermeasures have vulnerabilities themselves. For this reason, vulnerability can never be zero, and thus risk can never be totally eliminated.

Explanation:

also we need to be protected from scams and stuff

7 0
3 years ago
Write the half function. A function call and the functionprototype
EastWind [94]

Answer:

C code for half()

#include<stdio.h>

void half(float *pv);

int main()

{

float value=5.0;  //value is initialized  

printf ("Value before half: %4.1f\n", value); // Prints 5.0

half(&value);  // the function call takes the address of the variable.

printf("Value after half: %4.1f\n", value); // Prints 2.5

}

void half(float *pv) //In function definition pointer pv will hold the address of variable passed.

{

*pv=*pv/2;  //pointer value is accessed through * operator.

}

  • This method is called call-by-reference method.
  • Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
  • The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(),  we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
  • Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.

Output:

Output is given as image.

3 0
3 years ago
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