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d1i1m1o1n [39]
3 years ago
5

How to solve -13=5(1 4m)-2m?

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0
First, you would multiply: -13 = 70m - 2m. Then, you subtract the like terms, which would be 70m - 2m: -13 = 68m. You are looking for what m is, so you would divide 68 on both sides: m = - 13 / 68. In math, people would usually like fractions more than decimals, but if you are looking for the decimal number, it would be m ≈ - 0.19.
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What is the distance between the point (-7,3) and (4, -5) on a coordinate plane?
Evgesh-ka [11]
To find this, use the distance formula. D= square root over... (x2-x1)^2+ (y2-y1)^2. Now plug in your coordinates.
D= square root... (4- -7)^2+ (-5-3)^2. Simplify. 4- -7=11 (two neg= positive) -5 -3= -8. So,
D= square root... 11^2+ -8^2. Simplify. 11^2= 121. And -8^2=64. Now just take the square root after adding. 121+64= 185. And the square root of 185 isn’t a whole number, so your final answer is D= (square root over) 185. Hope this helps
7 0
3 years ago
Question 4 of 10
nadezda [96]

Answer:

<A=<D

Step-by-step explanation:

I just took the quiz

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3 years ago
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Which value of h would horizontally translate a parabola to the right 4 units?
bonufazy [111]
The answer is -4 for it to be translated right.
6 0
3 years ago
Paul and Jim work at a t-shirt factory. They pack t-shirts in boxes and send them
Gwar [14]

Answer:

Jim's box hold more t-shirts by 3 cubic feet

Step-by-step explanation:

Jim's box length = 2 feet

Jim's box breadth = 4 feet

Jim's box height = 6 feet

Volume of box =Length \times Breadth \times Height = 2 \times 4 \times 6 = 48 feet^3

Paul's box length = 3 feet

Paul's box breadth =5 feet

Paul's box height = 3 feet

Volume of box =Length \times Breadth \times Height =3 \times 5 \times 3 = 45 feet^3

So,Jim's box hold more t shirts by (48-45 = 3 cubic feet )

So, Option C is true

Jim's box hold more t-shirts by 3 cubic feet

3 0
3 years ago
Need help ASAP! I’ll give brainliest;) No links please, will report.
ehidna [41]

Answer:

side 1=5x^2+103x+40

side2=5x^3-43+100

side 3=A {let}

we have

perimeter of triangle=side 1+ side2 +side3

5x^4+5x^3+5x^2+50x+100=5x^2+103x+40+5x^3-

43+100+A

A=5x⁴+5x³+5x²+50x+100-5x³-5x²-103x-97

A=5x⁴-53x+3 is your answer

3 0
3 years ago
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