Can you please help me THAKS! IN A HURRY IT'S midnight and I am trying to finish my work from home My parents allow me to ask
1 answer:
Answer: 6.82
Step-by-step explanation:
So we know the Law of Sines which is that Sin A/a = Sin B/b = Sin C/c. The Sin on top of the fraction is the angle, and the letter on the bottom is the side opposite from that angle.
Our first step is going to be finding the last angle. We have 2 angles already, but one that's missing. We know that all triangles' angles add up to 180, so we can add 68+40=108. Then do 180-108 to get 72. Now we know the third and final angle.
Ok so back to Law of Sines. Now we can plug into that equation. We only need Sin A/a = Sin B/b (It doesn't matter what order you put them in). And remember the lowercase letter at the bottom represents the OPPOSITE side from one of the angles. Since the problem wants the side opposite Sin 68, let's set up a proportion.
Set up we have what we know. We know one side, and opposite that is the angle we already solved for. Now we can cross multiply and end up with:
Since we want to isolate x, we can divide each side by Sin 72.
x= 7(Sin 68)/Sin 72
So now let's put it into the calculator:
7(Sin 68)=6.2853
Now let's divide 6.2853/Sin 72
And you should be left with 6.82 if you round it!
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keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.
we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.
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Answer:
A.
Step-by-step explanation:
We have that, ΔABC is transformed to get ΔA''B''C''.
We see that the following transformations are applied:
1. Reflection across x-axis i.e. flipped across x-axis.
Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.
2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.
So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.
Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.