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zzz [600]
3 years ago
6

In rhombus fmkw mk=12 fk= 16 m

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

If it is area your looking for.

Area = product of diagonal lengths divided by 2

Area = 12* 16 /2

         =192/2  = 96.

IF it is the side length of the rhombus:

apply Pythagoras theorem since the diagonals always meet at 90°.

L =√(12² + 16²)

L= √400 = 20

          

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Step-by-step explanation:

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  • x=(-4y+1)/2
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3×(-4y+1)/2+5y=7b

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2 years ago
If g(x) = 5x2^2 - 10x + 9 and h(x) = -3x3^3+ 5x - 6, find g(x) - h(x)?
AnnZ [28]

Answer:

B)g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

Step-by-step explanation:

Here, the given functions are:

g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6

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(5x^2- 10x + 9)  - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+  (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15

⇒(5x^2- 10x + 9)  - ( -3x^3+ 5x - 6) =  3x^3 - 5x^2 - 15x + 15

B) Hence, g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

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I'm confused because the answer is 220 quarts.
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