In rhombus fmkw mk=12 fk= 16 m
1 answer:
If it is area your looking for.
Area = product of diagonal lengths divided by 2
Area = 12* 16 /2
=192/2 = 96.
IF it is the side length of the rhombus:
apply Pythagoras theorem since the diagonals always meet at 90°.
L =√(12² + 16²)
L= √400 = 20
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