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bixtya [17]
3 years ago
9

What is 58,256 multiplied by 2/3? Is the product greater or less then the fraction

Mathematics
1 answer:
garik1379 [7]3 years ago
5 0
The answer is 38,837.33294496 and yes it is greater than the fraction ( don’t flame me if I get I wrong ok please )
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What answer is correct? The audio is just reading the question.
RSB [31]

Answer:

its 7

Step-by-step explanation:

3 0
3 years ago
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Given that f(x) = x^2 - 11x + 18 and g(x) = x-9, find f(x) + g(x)
liberstina [14]

Answer:

f(x) + g(x) = x² - 10x + 9

General Formulas and Concepts:

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 11x + 18

g(x) = x - 9

<u>Step 2: Find f(x) + g(x)</u>

  1. Substitute:                              f(x) + g(x) = x² - 11x + 18 + x - 9
  2. Combine like terms (x):          f(x) + g(x) = x² - 10x + 9

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3 0
3 years ago
If the mean, median and mode of a distribution are 5, 6, 7 respectively, then the distribution is:
QveST [7]
<span>the distribution is 43

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3 0
3 years ago
Rectangle
Viefleur [7K]

Answer:

  21 square units

Step-by-step explanation:

The sides of the rectangle are aligned with the coordinate grid, so we can easily find its dimensions.

AB lies on the line y = -2, so the horizontal extent is the difference in x-values:

  6 - 3 = 3

BC lies on the line x = 6, so the vertical extent is the difference in y-values:

  5 -(-2) = 7

The area is the product of these two dimensions:

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The area of the rectangle is 21 square units.

3 0
3 years ago
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Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

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3 years ago
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