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3 years ago

12

Four plants orbit a star at the following distances.Which one is the closes to the star?

1 answer:

vredina [299]3 years ago

5 0

Answer: Easily A.

Step-by-step explanation: All you have to do is look at the power of the tens. The one that is the least is A. Since none of the other choices are equal to or less than 10^7, A is your answer. In scientific notation, you almost always look at the 10^x first.

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Please help, I’ll mark as brainliest.

Crazy boy [7]

Step-by-step explanation:

H(x)=

$\frac{f(x)}{g(x)}$

If g(x) values =0, h(x) will be undefined.

So f(x)=0, h(x) will be undefined.

Zo find values of f(x) equal 0.

That is when x=2. So the answer to first solution is 2.

h(x) is negative when (-oo, -3) U (2,oo)

4 0

2 years ago

X-6>37 answer of equality

GrogVix [38]

$x - 6 \ \textgreater \ 37 \\ \\ x \ \textgreater \ 37 + 6 \\ \\ x \ \textgreater \ 43 \\ \\$

The final result is: x > 43.

8 0

3 years ago

Simplify: 5(3x -4) - 6( 4 - 3x)

VikaD [51]

Answer:

33x-44

Step-by-step explanation:

15x-20-24+18x

33x-44

5 0

3 years ago

Solve for s. 2/3 s + 5/6 s = 21 Enter the answer, as a whole number or as a fraction in simplest form, in the box.

dem82 [27]

The whole problem is in the picture. I Hope this helps

6 0

3 years ago

Read 2 more answers

Find x, if 3x − 5(y + x ) ^2 = 16 and 4x + 2(y + x )^ 2 = 30

lana66690 [7]

Answer:

x = 7

Step-by-step explanation:

Start by solving for $(y+x)^2$ which is a common expression for both equations. Then in the first equation:

$3\,x5\,(y+x)^2=16\\3x-16=5\,(y+x)^2\\(y+x)^2=\frac{3\,x-16}{5}$

and in the second equation:

$4\,x+2\,(y+x)^2=30\\2\,(y+x)^2=30-4\,x\\(y+x)^2=15-2\,x$

Now we make the two $(y+x)^2$ expressions equal so we get:

$\frac{3\,x-16}{5} =15-2\,x\\3\,x-16=75-10\,x\\13\,x=75+16\\13\,x=91\\x=7$

8 0

3 years ago