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USPshnik [31]
3 years ago
5

Find the solutions to the equation below 9x^2 -81=0

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Step-by-step explanation:

=

−

±

2

−

4

√

2

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

9

2

−

8

1

=

0

9x^{2}-81=0

9x2−81=0

=

9

a=

a=9

=

0

b={\color{#e8710a}{0}}

b=0

=

−

8

1

c={\color{#129eaf}{-81}}

c=−81

=

−

0

±

0

2

−

4

⋅

9

(

−

8

1

)

√

2

⋅

9

x=2⋅9−0±02−4⋅9(−81)​​

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Find the interest rate r compounded monthly if the principal P = $4,300 reaches the future value F = $4,720 in t = 6 years. Roun
kirza4 [7]

Answer:

  1.55%

Step-by-step explanation:

Fill in the values and solve for the rate using the future value formula.

  FV = P(1 +r/n)^(nt)

  4720 = 4300(1 +r/12)^(12·6)

  (4720/4300)^(1/72) = 1 +r/12

  r = 12(4720/4300)^(1/72) -1) ≈ 0.015542

The annual interest rate is about 1.55%.

4 0
3 years ago
A=5x+20
kirza4 [7]

Answer:

video rum is eryn rice of a local food store to the point of the lord and of a man of his name poltergeist and the lord God is the lord God is not in the land and he is the lord of Israel as he will be the

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3 years ago
A fair die is rolled 5 times. what is the probability of having no 2 and no 5 among the rolls ?
morpeh [17]
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6 0
3 years ago
How do u round 14,494 to the nearest thousand
Reil [10]
Look at the digit one number place to the right of the thousands place, the hundreds. In this case it is another 4. Since it is less than 5, the thousands place will stay the same. If it were 5 or greater, the thousands place would go up by one number. 14,494 rounded to the nearest thousand is 14,000
7 0
3 years ago
Find the midpoint of the segment with the given endpoints. (9.-9) and (2.-10)​
kondor19780726 [428]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{(5.5 \: , \: -  9.5)}}}}}

Step-by-step explanation:

Let the points be A and B

Let A ( 9 , -9 ) be ( x₁ , y₁ ) and B ( 2 , - 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the</u><u> </u><u>midpoi</u><u>nt</u>

\boxed{ \sf{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} }}

\longrightarrow{ \sf{midpoint = ( \frac{9 + 2}{2} , \:  \frac{ - 9  + ( - 10)}{2}}} )

\longrightarrow{ \sf {midpoint = ( \frac{11}{2} \: , \:  \frac{ - 9 - 10}{2}})}

\longrightarrow{  \sf{midpoint = (5.5 \: , \:  \frac{ - 19}{2}}} )

\longrightarrow{ \sf{midpoint = (5.5 \: , - 9.5}})

Hope I helped!

Best regards! :D

5 0
2 years ago
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