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2 years ago

Order numbers from least to greatest 16,4, 1.64, 1.6, 16.099

Mathematics

2 answers:

Paladinen [302]2 years ago

7 0

These are from least to greatest 1.6,1.64,16,4,16.009

vladimir2022 [97]2 years ago

3 0

1.6 ,16.099 ,1.64 ,4 ,16 i hope it helped you

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A man has a mass of 120kg, he reduces his mass by 15%, how many kilograms is that

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If p:q=2/3:3 and p:r=3/4:2/3 calculate the ratio p:q:r. Giving the answer in its simplest form

adelina 88 [10]

Answer:

Given

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3 = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2 = 3/2

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

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p/r = 2/3 x 3/2 = 6/4

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3 years ago

PLEASE HELP PRE CAL!!

Len [333]

Answer:

Width = 2x²

Length = 7x² + 3

Step-by-step explanation:

∵ The area of a rectangle is $14x^{4}+6x^{2}$

∵ Its width is the greatest common monomial factor of $14x^{4}$ and 6x²

- Let us find the greatest common factor of 14 , 6 and $x^{4}$ , x²

∵ The factors of 14 are 1, 2, 7, 14

∵ The factors of 6 are 1, 2, 3, 6

∵ The common factors of 14 and 6 are 1, 2

∵ The greatest one is 2

∴ The greatest common factor of 14 and 6 is 2

- The greatest common factor of monomials is the variable with

the smallest power

∴ The greatest common factor of $x^{4}$ and x² is x²

∴ The greatest common monomial factor of $14x^{4}$ and 6x² is 2x²

∴ The width of the rectangle is 2x²

To find the length divide the area by the width

∵ The area = $14x^{4}+6x^{2}$

∵ The width = 2x²

∴ The length = ( $14x^{4}+6x^{2}$ ) ÷ (2x²)

∵ $14x^{4}$ ÷ 2x² = 7x²

∵ 6x² ÷ 2x² = 3

∴ ( $14x^{4}+6x^{2}$ ) ÷ (2x²) = 7x² + 3

∴ The length of the rectangle is 7x² + 3

8 0

2 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago