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Dimas [21]
3 years ago
8

If there is one-third of a pizza left, and Becky only wants to eat one-half of it, how much of the pizza does she want?

Mathematics
2 answers:
netineya [11]3 years ago
6 0

Answer:

1/6

Step-by-step explanation:

natali 33 [55]3 years ago
5 0
She wants to eat 1/6 of the pizza.
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What two ratios are equivalent to 11/12
skad [1K]
(11 x2) (12 x 2)
22 : 24 

or 

(11x3) (12 x 3)
33 : 36

both are equivalent to 11/12


6 0
3 years ago
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Find the mistake in the problem. tell what is is.<br>6th grade math ​
nirvana33 [79]
He / she didn’t drop down the 2 after subtracting 19 from 242, instead he / she dropped down a 0.
7 0
3 years ago
Find the amplitude and the equation of the midline of the periodic function.
Masja [62]

Answer:

Option B. Amplitude =3 midline is y =2.

Step-by-step explanation:

In the graph attached we have to find the amplitude and midline of the periodic function.

Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2

=  (5-(-1))/2 = (5+1)/2 =6/2 =3.

Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.

Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.

6 0
3 years ago
Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
P=2L+2W<br><br>solve for L <br>do the entire equation
VashaNatasha [74]
HEY THEIR!!

Taking commen 2 in RHS
p = 2 (L+W )

Divide by 2 on both sides.
p/2 = L+W

Subtract W on both sides.
p/2 - W = L

or L = p/2- W

HOPE IT HELPS YOU
6 0
3 years ago
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