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3 years ago

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The underground ride is 861 mater long, what isthis number rounded to the nearest 100?

2 answers:

KATRIN_1 [288]3 years ago

8 0

the underground ride is 861 mater long, what isthis number rounded to the nearest 100?

Answer:

861 ≈ 900

lara [203]3 years ago

4 0

Answer:

900

Step-by-step explanation:

Since you are doing it to the nearest 100, you look at the ten's place.

If the number is higher then 5, you round up

If its lower, you round it to the digit already in the hundreds place.

In the question, the digit is 6, which means it will be rounded up

so instead of 800, it would be 900

Hope this helped :D

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Question in the link below.

olga_2 [115]

The 5x and the combination of (40° + x) are "vertical angles".
Vertical angles are equal.
So
5x = 40° + x

Subtract 'x' from each side: 4x = 40°

Divide each side by 4 : x = ?

3 0

3 years ago

Read 2 more answers

The length of the triangle for the pool table is the twice the sum of 5 and a number. If the rack is

gayaneshka [121]

Answer:

30 + 6x inches

Step-by-step explanation:

Let the required number be x

If the length of the triangle for the pool table is the twice the sum of 5 and a number

L = 2(5+x)

L = 10+2x

Since the triangle is quadilateral, this means that all sides are equal

Perimeter = 3L

Perimeter = 3(10+2x)

Perimeter = 30+6x

Hence the perimeter, in inches, of the triangle is 30 + 6x inches

7 0

3 years ago

SOMEONE HELP MEEEEEE 75 POINTS TO THE PERSON THAT HELPS

Tresset [83]

Answer:

Part 1) $9x-7y=-25$

Part 2) $2x-y=2$

Part 3) $x+8y=22$

Part 4) $x+8y=35$

Part 5) $3x-4y=2$

Part 6) $10x+6y=39$

Part 7) $x-5y=-6$

Part 8)

case A) The equation of the diagonal AC is $x+y=0$

case B) The equation of the diagonal BD is $x-y=0$

Step-by-step explanation:

Part 1)

step 1

Find the midpoint

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{2-6}{2},\frac{-3+5}{2})$

$M=(-2,1)$

step 2

The equation of the line into point slope form is equal to

$y-1=\frac{9}{7}(x+2)\\ \\y=\frac{9}{7}x+\frac{18}{7}+1\\ \\y=\frac{9}{7}x+\frac{25}{7}$

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

$Ax+By=C$

where

A is a positive integer, and B, and C are integers

$y=\frac{9}{7}x+\frac{25}{7}$

Multiply by 7 both sides

$7y=9x+25$

$9x-7y=-25$

Part 2)

step 1

Find the midpoint

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{1+5}{2},\frac{0-2}{2})$

$M=(3,-1)$

step 2

Find the slope

The slope between two points is equal to

$m=\frac{-2-0}{5-1}=-\frac{1}{2}$

step 3

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

Find the slope of the line perpendicular to the segment joining the given points

$m1=-\frac{1}{2}$

$m1*m2=-1$

therefore

$m2=2$

step 4

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=2$ and point $(1,0)$

$y-0=2(x-1)\\ \\y=2x-2$

step 5

Convert to standard form

Remember that the equation of the line into standard form is equal to

$Ax+By=C$

where

A is a positive integer, and B, and C are integers

$y=2x-2$

$2x-y=2$

Part 3)

In this problem AB and BC are the legs of the right triangle (plot the figure)

step 1

Find the midpoint AB

$M1=(\frac{-5+1}{2},\frac{5+1}{2})$

$M1=(-2,3)$

step 2

Find the midpoint BC

$M2=(\frac{1+3}{2},\frac{1+4}{2})$

$M2=(2,2.5)$

step 3

Find the slope M1M2

The slope between two points is equal to

$m=\frac{2.5-3}{2+2}=-\frac{1}{8}$

step 4

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{8}$ and point $(-2,3)$

$y-3=-\frac{1}{8}(x+2)\\ \\y=-\frac{1}{8}x-\frac{1}{4}+3\\ \\y=-\frac{1}{8}x+\frac{11}{4}$

step 5

Convert to standard form

Remember that the equation of the line into standard form is equal to

$Ax+By=C$

where

A is a positive integer, and B, and C are integers

$y=-\frac{1}{8}x+\frac{11}{4}$

Multiply by 8 both sides

$8y=-x+22$

$x+8y=22$

Part 4)

In this problem the hypotenuse is AC (plot the figure)

step 1

Find the slope AC

The slope between two points is equal to

$m=\frac{4-5}{3+5}=-\frac{1}{8}$

step 2

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{8}$ and point $(3,4)$

$y-4=-\frac{1}{8}(x-3)$

$y=-\frac{1}{8}x+\frac{3}{8}+4$

$y=-\frac{1}{8}x+\frac{35}{8}$

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

$Ax+By=C$

where

A is a positive integer, and B, and C are integers

$y=-\frac{1}{8}x+\frac{35}{8}$

Multiply by 8 both sides

$8y=-x+35$

$x+8y=35$

Part 5)

The longer diagonal is the segment BD (plot the figure)

step 1

Find the slope BD

The slope between two points is equal to

$m=\frac{4+2}{6+2}=\frac{3}{4}$

step 2

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=\frac{3}{4}$ and point $(-2,-2)$

$y+2=\frac{3}{4}(x+2)$

$y=\frac{3}{4}x+\frac{6}{4}-2$

$y=\frac{3}{4}x-\frac{2}{4}$

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

$Ax+By=C$

where

A is a positive integer, and B, and C are integers

$y=\frac{3}{4}x-\frac{2}{4}$

Multiply by 4 both sides

$4y=3x-2$

$3x-4y=2$

Note The complete answers in the attached file

3 0

3 years ago

Determine the values of the parameter s for which the system has a unique solution, and describe the solution. sx 1 minus 2 sx

JulijaS [17]

Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.

Answer:

For the system of equations to be unique, s can take all values except 2 and -2

Step-by-step explanation:

$2sx_{1} + 4x_{2} = -3\\2x_{1} + sx_{2} = 4$

$\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]$

For the system to have a unique solution, $\begin{vmatrix} 2s & 4 \\ 2 & s \end{vmatrix} \neq 0$

$2s^{2} -8 \neq 0\\2s^{2}\neq 8\\s^{2}\neq 4\\s \neq 2 or -2$

6 0

3 years ago

Find the area of the figures.

levacccp [35]

Answer:

First one: 114

Second one: 64

Step-by-step explanation:

For the first one, you can break apart the shapes to a square and a rectangle

The square is 7 x 7 (12 - 5 = 7)

The rectangle is 13 x 5

The square is 49

The rectangle is 65

Add them together

The first one is 114

For the second one you can break it apart to a triangle and a rectangle

The rectangle is 4 x 12

The triangle is 0.5 * 8 * 4 [8 is 12 - 4 (base)]

The rectangle is 48

The triangle is 16

Add them together

48 + 16 = 64

The second one is 64

6 0

2 years ago