The answer is 8 and 13
<span>
y = ax + b
y = 4, x = 1 </span>⇒ 4 = a + b
y = 6, x = 3 ⇒ 6 = 3a + b
Solve the system of equation:
a + b = 4
3a + b = 6
______
b = 4 - a
3a + b = 6
______
3a + 4 - a = 6
2a + 4 = 6
2a = 6 - 4
2a = 2
a = 2/2 = 1
b = 4 - a = 4 - 1 = 3
So, the function rule is: y = x + 3
Thus, if x = 7, then y = 7 + 3 = 10
If x = 10, then y = 10 + 3 = 13
x y
1 4
3 6
4 7
5 8
7 10
10 13
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
B 25.0 is the right answer
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>
Note the following identities: tan² x = sec²x - 1

tan² x + sec x = 1
(sec² x -1) + sec x = 1
sec² x + sec x - 2 = 0
(sec x + 2)(sec x - 1) = 0
sec x + 2 = 0 sec x - 1 = 0
sec x = -2 sec x = 1

By knowing the volume of a triangle and that the triangle has all equal sides