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3 years ago

5

Find the polynomial. (-1/3,4) is the solution set of

1 answer:

iragen [17]3 years ago

6 0

Step-by-step explanation:

d abhddas jdhsa

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Find the area of a rectangle with a length of 5 1/3 inches and a width of 2/3 inch

neonofarm [45]

Step-by-step explanation:

$length \: of \: rectangle \\ l = 5 \frac{1}{3} \: inches = \frac{16}{3} \:inches \\ \\ width \: of \: rectangle \: \\ w = \frac{2}{3} \: inch \\ \\ area \: of \: rectangle \\ = l \times w \\ \\ = \frac{16}{3} \times \frac{2}{3} \\ \\ = \frac{32}{9} \\ \\ \red{ \boxed{ \therefore area \: of \: rectangle = 3 \frac{5}{9} \: {inch}^{2} }}$

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3 years ago

What is the systems equation

m_a_m_a [10]

The third one is the answer

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4 years ago

What are two different ways of factoring:

dolphi86 [110]

Answer: -2(f + 5)
Explanation:

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3 years ago

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Cómo simplificar -3/4

Lunna [17]

No se puede simplificar ya. ✅

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3 years ago

Find the missing part. L=8, w=4, h=2. Find the diagonal of (d) of the retangular solid

marusya05 [52]

The diagonal of the rectangular solid is $d=2 \sqrt{21}$

Explanation:

The length of the rectangular solid is $l=8$

The width of the rectangular solid is $w=4$

The height of the rectangular solid is $h=2$

We need to determine the diagonal of the rectangular solid.

The diagonal of the rectangular solid can be determined using the formula,

$d=\sqrt{l^{2}+w^{2}+h^{2}}$

Substituting the values $l=8$ , $w=4$ and $h=2$ , we get,

$d=\sqrt{8^{2}+4^{2}+2^{2}}$

Squaring the terms, we get,

$d=\sqrt{64+16+4}$

Adding the terms, we have,

$d=\sqrt{84}$

Simplifying, we have,

$d=2 \sqrt{21}$

Thus, the diagonal of the rectangular solid is $d=2 \sqrt{21}$

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3 years ago