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3 years ago

(5m-4)/6 -1 = 4m - (3m+10)/2pls answer fast

Mathematics

1 answer:

Debora [2.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{(5m - 4)}{6} - 1 = 4m - \frac{(3m + 10)}{2}$

$= > \frac{5m - 4 - 6}{6} = \frac{8m - 3m - 10}{2}$

$= > \frac{5m - 10}{6} = \frac{5m - 10}{2}$

[Cross Multiplication]

=> 2(5m - 10) = 6(5m - 10)

=> 10m - 20 = 30m - 60

=> 60 - 20 = 30m - 10m

=> 40 = 20m

$= > m = \frac{40}{20}$

=> m = 2 (Ans)

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3 years ago

96 inches=_______feet?

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3 years ago

A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part. How long is e

Pachacha [2.7K]

Answer:

The longer part is 45 cm long and the shorter part is 25 cm long.

Step-by-step explanation:

Given:

A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part.

Now, to find the length of each part of the stick.

Let the shorter part be $x.$

So, the longer part is $x+20.$

Total length of the stick = 70 cm.

Now, to get the length of each part we solve an equation:

$(x)+(x+20)=70\\\\x+x+20=70\\\\2x+20=70\\\\Subtracting\ both\ sides\ by\ 20\ we\ get:\\\\2x=50\\\\Dividing\ both\ sides\ by\ 2\ we\ get:\\\\x=25.$

The length of the shorter part is 25 cm.

Now, substituting the value of $x$ :

$x+20\\\\=25+20\\\\=45\ cm.$

The length of longer part is 45 cm.

Therefore, the longer part is 45 cm long and the shorter part is 25 cm long.

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3 years ago

Given that a function, g, has a domain of -20 sxs 5 and a range of -5 s g(x) s 45 and that g(0) = -2 and g(-9) = 6, select the s

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Answer:

Step-by-step explanation:

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3 years ago

If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n

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Let $x$ be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is $x+4039,$ so our answer is $\boxed{4039}.$

For completeness, though, let's solve for the value of $x$ that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term $a_1,$ last term $a_n,$ and $n$ terms, is $\frac{n(a_1+a_n)}{2}.$ Plugging in our known values gives us the equation $\frac{4040(2x+4039)}{2}=2020,$ which simplifies to $2x+4039=1.$ Thus, $x=-2019,$ so the 4040 consecutive integers are $-2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020.$ Notice how everything except the $2020$ cancels out!

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3 years ago

(5m-4)/6 -1 = 4m - (3m+10)/2pls answer fast​

(5m-4)/6 -1 = 4m - (3m+10)/2pls answer fast