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Murljashka [212]
3 years ago
15

Go Math Math Homework Lesson 8.4

Mathematics
2 answers:
kvasek [131]3 years ago
3 0
Breanna exercises for 4 and 1/2 hours during the six days.

To find the answer, we have to multiply 3/4 by 6.

To do this, we change 6 to 6/1 and multiply straight across.

3/4 x 6/1 = 18/4 = 9/2

9/2 is the same as 4 and 1/2
Inessa [10]3 years ago
3 0
<h2><u>By:</u> </h2><h3><em>Syrenity Holford</em></h3><h2><u></u></h2><h2><u>Answer:</u></h2><h3><em>Breanna exercises for 4 and 1/2 hours during the six days.</em></h3><h3><em></em></h3><h3><em>To find the answer, we have to multiply 3/4 by 6.</em></h3><h3><em></em></h3><h3><em>To do this, we change 6 to 6/1 and multiply straight across.</em></h3><h3><em></em></h3><h3><em>3/4 x 6/1 = 18/4 = 9/2</em></h3><h3><em></em></h3><h3><em>9/2 is the same as 4 and 1/2</em></h3>

<em />

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Further analysis of the data for the breakfast cereals in exercise 46 looked for an assocation between fiber content and calorie
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Complete Question:

Attached below as picture.

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planes x and y and points J, K, L, M and N are shown. exactly hiw many points contain points J, K, and N ? 0 1 2 3​
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Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

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2 years ago
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