All categories

3 years ago

Solve x in the equation X2-12x+36=90

Mathematics

1 answer:

Dahasolnce [82]3 years ago

3 0

Step-by-step explanation:

2x-12x+36 =90

-10x + 36 = 90

-10x =54

x = - 5.4

You might be interested in

Which of the following shows the division problem below in synthetic division form? (6x^3+x^2-3)/(x-7)

PSYCHO15rus [73]

Answer:

Option C.

Step-by-step explanation:

If a polynomial P(x) is divided by (x-c), then we write leading coefficients inside the synthetic division line and c outside the synthetic division line.

The given division problem is

$\dfrac{6x^3+x^2-3}{x-7}$

Here,

$x-c=x-7\Rightarrow c=7$

The numerator polynomial can be written as

$P(x)=6x^3+x^2+0x-3$

So, the coefficients of numerator are 6, 1, 0, -3.

The synthetic division form for given division problem is

7 | 6 1 0 -3

Therefore, the correct option is C.

5 0

3 years ago

How to work out the volume of a cone?

Romashka [77]

Volume of a cone = πr²h/3. π=3.14 R=radius. hope this helps you :)

4 0

3 years ago

Almost done. I need help with this part

valentina_108 [34]

Answer:

$\%Percent = 14.3\%$

Step-by-step explanation:

Required

15 is what percentage of 105

To do this, simply divide 15 by 105 multiplied by 100%.

So, we have:

$\%Percent = \frac{15}{105} * 100\%$

$\%Percent = \frac{15*100}{105}\%$

$\%Percent = \frac{1500}{105}\%$

$\%Percent = 14.3\%$ --- approximated

8 0

3 years ago

The sum of 3 times a number and 7 is 25

hammer [34]

Mathematically written:

3 * x + 7 = 25

3x + 7 = 25

3x = 25 - 7

3x = 18

x = 18 / 3

x = 6

Proof:

3 * 6 + 7 = 25

18 + 7 = 25

25 = 25 → both sides of the equation are equal, our answer is correct

Notes:

A number - Is an unknown number, called a variable, which in this case is substituted by the letter x.

Hope it helped,

BioTeacher101

5 0

3 years ago

Read 2 more answers

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago