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UkoKoshka [18]
2 years ago
8

What is the answer to this, there were 22869 children, 49563 men, and 2872 more women than men at the fair. How many people were

at the fair?
Mathematics
1 answer:
iVinArrow [24]2 years ago
3 0

Total number of children at the fair = 22,869

Total number of men at the fair = 49,563

Since, there were 2872 more women than men at the fair.

So, total number of women at the fair = 49,563 + 2872

= 52,435

So, total number of people

= Total number of children + Total number of men + Total number of women

= 22,869 + 49,563 + 52,435

= 124,867

Therefore, there are 124,867 total people at the fair.

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Please HELP ASAP!!! The dot plot show the number of hours teenagers spent on two different websites last week. Which statement i
Delvig [45]

Answer:

(F.) the mode of the data for website K is greater than the mode of the data from website L

Step-by-step explanation:

Mode simply means the parameter that occurs the most.

In website K, the one that occurs the most is 8 hours while in website L, the one that occurs the most is 2 hours.

This means that mode of website K is greater than that of website L.

Thus,statement F is correct

Range is the difference between the highest value and the lowest value..

For website K, Range = 14 - 1 = 13

For website L, Range = 13 - 1 = 12

Thus,range of both websites are not the same and as such statement G is wrong.

For a symmetrical distribution, the left and right hand sides of the centre value line of the distribution have to mirror each other.

In this case neither website K nor L have that. Thus, statement H is not correct.

Skewed to the left means that more o

dot points are found to the left of the graph.

For website L, more dot points are located to the left while for website K, it's not the case. Thus, statement J is not correct

8 0
3 years ago
Read 2 more answers
Replace * with a monomial in such a way, that the trinomial becomes a perfect square. *+12x+1
Mrrafil [7]

Answer: * = 36x^2

Note: Im guessing you're here for rsm struggles. That's how I found this question. I searched the web for the answer to this rsm problem, but I couldnt find it. I was happy to find this brainly link, but annoyed to find it was unanswered. I did the problem, and now i'll help future rsm strugglers out. Thanks for posting this question.

Step-by-step explanation:

Ok, so we know that trinomials like this are squares of binomials. this in mind, we know that it can also be written as (x+y)^2. (also brainly's exponents feature used to be better, if the exponents are confusing you, comment.) Using the (x+y)^2 equation, you know that by simplifying it, you get x^2+2xy+y^2. Basically we're looking for x^2. Using the middle term, 2xy, or 12x in this equation, we can find x. since we know the square root of 1 is 1, we know 12=2x. This is kinda confusing, but basically since the answer is 6, we know that the x-term is 6x. We square 6x and get 36x^2. guaranteed to work on the rsm student portal, i'm in rsm and i just answered this question.

Hope this helps! Also, im not usually too active on brainly unless im looking for HW answers, so if you understand this explanation and you see a confused comment, help out a friend and answer it. Happy holidays!

4 0
2 years ago
Which relation has both domain and range of all real numbers
Mama L [17]

Answer:

C

Step-by-step explanation:

All real numbers means all numbers positive and negative

Therefore, it would have to be C because the others dont have both positives and negatives for their domain and range reaches

4 0
3 years ago
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
Bonjour
solmaris [256]
<span>3 + t = 2 x t + 7    t =4 et x=0   vraie
</span><span>9 x (t-6) = 3 x t     t=4 et x=0    vraie
</span><span>4 x (t - 1) = t x t     t=2 st x=0    vraie

No, 25 cm c'est un 40 ou 41
No 23 cm c'est un 37



</span>
6 0
3 years ago
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