The end result is production of four haploid cells (n chromosomes, 23 in humans) from the two<span> haploid cells (with n chromosomes, each consisting of </span>two<span> sister chromatids) produced in </span>meiosis<span> I. The four main </span>steps of Meiosis II<span> are: Prophase </span>II<span>, Metaphase </span>II<span>, Anaphase </span>II<span>, and Telophase </span>II<span>.</span>
Answer and Explanation:
Bovine pancreatic trypsin inhibitor (BPT I) is a small globular protein and it inhibits the proteolytic enzymes like trypsin. BPTI is composed of ∝ helices, β sheets and 3 disulfide bonds. Due to these BPTI is a stable protein in its tertiary structure. It is almost inert to denaturation by urea and exhibits denaturation below 100 degree, only in highly acidic solutions. When all the disulfide bonds in BPTI are reduced, the protein is unfolded at room temperature and can reform three correct S-S pairings in native confirmation. if the 6 cysteine residues are reduced and unfolded in urea, the re-oxidation would yield 3 pairs with probability of first pair with 5, second pair with 3 and the third pair with 1 cysteine residues. Therefore, 5 x 3 x 1 = 15 combinations are possible accounting for 7% of protein refolding.
Answer:
Because certain varieties of blue-green algae can produce toxins that are linked to illness
Explanation:
I would go with mathmatical formula because of physics and what not but I'm not completely sure so if you have a different possible answer you think would be better, go with that :)
