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Marizza181 [45]
3 years ago
8

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

3-inch radius

A = sq. in.

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer: A =  (27/4)√3 in²


Explanation:


You are required to calculate the area, A, of an equilateral triangle, when you know its radius is 3 inches.


The radius of an equilateral triangle is the radius of the cirscumscribed circle.


The equilateral triangle has several characteristics which can be geometrically deduced:


  • Three congruent sides (by definition)
  • Three 60° internal angles
  • If you call the length of the sides x, and the radius of the circumscribed circle r, then:

       r = x √3 / 3 ⇒ x = r√3

       Area = [√3 / 4] x²

  • Combining the two previous relations, you deduce:

        Area = [3 √3 / 4] r²

By substituting the given radius, you find the area of the equilateral triangle:

            Area = [3 √3 / 4] x² = [3 √3 / 4] (3 in)² = 27√3 / 4 in²

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What is 98/128 in simplest form
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Two card decks are drawn from a standard 52-card deck, without replacement. Find the probability that they are both aces.
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Twenty-five percent of the customers entering a grocery store between 5 P.M. and 7 P.M. use an express checkout. Consider five r
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Step-by-step explanation:

Download docx
6 0
3 years ago
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
3 years ago
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