Answer:
There are two more sides on a hexagon than on a quadrilateral
Step-by-step explanation:
If the hexagon has 6 sides, and the quadrilateral has 4, then 6-4=2
Answer:
The coordinates of E are
.
Step-by-step explanation:
The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.
Vectorially speaking, dilation is defined by the following operation:
(1)
Where:
- Point of reference.
- Original point.
- Dilated point.
- Dilation factor.
By applying this operation, point B becomes point D:
, 
![D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%280%2C0%29%20%2B%20k%5Ccdot%20%5B%280%2C4%29-%20%280%2C0%29%5D)




Lastly, we transform point C into point E by applying the same operation:
,
and 
![E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%280%2C0%29%20%2B%20%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20%5B%283%2C0%29-%280%2C0%29%5D)

The coordinates of E are
.
Answer:
0.0062
Step-by-step explanation:
Let X be the diagnosed blood sugar level.
Probability of committing a Type II error = Probability of failing to detect the disease when the person has the disease = Probability that the diagnosed blood sugar level is less than or equal to 125 =

![= P[Z\le (125 - 150)/10]](https://tex.z-dn.net/?f=%3D%20P%5BZ%5Cle%20%28125%20-%20150%29%2F10%5D)
![=P[Z \le -2.5]](https://tex.z-dn.net/?f=%3DP%5BZ%20%5Cle%20-2.5%5D)
= 0.0062
(x-y)(x^2+xy+y^2)
The first parentheses contain the cubed root of both the terms so x and y respectively. second parentheses follows the formula (a^2 + ab + b^2)
x corresponds to a and y corresponds to b. The signs are what change depending on what the original equation is. Since the original is a subtraction then the signs are -/+/+. you can remember it using the acronym SOAP. (S = same, O = opposite, AP = always positive) So the first sign is x - y (same as subtraction from original), the second and third are x^2 + xy + y^2 (opposite is a plus, and the last sign is always a positive.