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worty [1.4K]
3 years ago
5

Nancy borrows $5000 at a rate of 16% interest per year. What is the amount due at the of 5 hears if the interest is compunded co

ntinuously?
Mathematics
2 answers:
Julli [10]3 years ago
4 0
The amount due in 5 years is 11,000
ElenaW [278]3 years ago
4 0

Answer:

D is 11,000

Step-by-step explanation:

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What is the sum of the zeros of the function: y= x^2 - 5x + 6?
yawa3891 [41]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y = 0

Quadratic formula

x = [5 ± √(5² – 4·1·6)] / [2·1]

 = [5 ± √1] / 2

 = [5 ± 1] /2

 = 2, 3

sum of zeros = 5

7 0
3 years ago
Answer CORRECTLY !!!!! Will mark brainliest !!!!
mash [69]

Answer:

g(q) = \frac{5q}{8}

Step-by-step explanation:

Given

- 7q + 12r = 3q - 4r

Rearrange making r the subject

Add 7q to both sides

12r = 10q - 4r ( add 4r to both sides )

16r = 10q ( divide both sides by 16 )

r = \frac{10q}{16} = \frac{5q}{8} , thus

g(q) = \frac{5q}{8}

4 0
3 years ago
Read 2 more answers
Area of 23ft^2 what is the length of a square
pentagon [3]

Step-by-step explanation:

Area=23ft²

Side=√23ft²

Side=4.8ft

4 0
2 years ago
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g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o
natali 33 [55]

Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0
3 years ago
Factor completely: 4x^3 - 36x
ivanzaharov [21]
You would take out a 4x out of both terms because this is a common factor 
4x^3-36x
4x(x^2-9) 
and then you would notice that (x^2-9) is a difference of squares, so that factors out too 
4x(x-3)(x+3)
that is all you can factor! hope this helps
3 0
2 years ago
Read 2 more answers
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