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GalinKa [24]
2 years ago
11

HELP! PLEASE! NEED THE ANSWER TONIGHT!

Mathematics
1 answer:
zysi [14]2 years ago
5 0

2. ∠STR ≅ ∠STP

                                                             3. Definition of Perpendicular

4. ∠SRT ≅ ∠SPT

5. segment ST ≅ segment ST              5. Reflexive Property

6. ΔSRT ≅ ΔSPT                                    6. AAS Triangle Congruence Theorem

7. segment SP ≅ segment SR              7. CPCTC

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8 more than 5 times a number is -27 write a function
xxMikexx [17]

5x+8=-27

8 more means addition. -27 would be total. 5 times the number ( in this case x) would mean multiplication.

3 0
2 years ago
Determine the shaded areas part 2​
shutvik [7]

9514 1404 393

Answer:

  (a) cannot be determined

  (b) 44 cm^2

  (c) 87 m^2

  (d) 180 m^2

  (e) 132 m^2

Step-by-step explanation:

(a) missing a horizontal dimension

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(b) The difference between the bounding rectangle and the lower-left cutout is ...

  (8 cm)(7 cm) -(3 cm)(4 cm) = (56 -12) cm^2 = 44 cm^2

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(c) The difference between the bounding rectangle and the center cutout is ...

  (13 m)(7 m) -(4 m)(1 m) = (91 -4) m^2 = 87 m^2

__

(d) The difference between the bounding rectangle and the two cutouts is ...

  (20 m)(25 m) -(16 m)(20 m) = (20 m)(25 -16) m = (20 m)(9 m) = 180 m^2

__

(e) The difference between the bounding rectangle and the two cutouts is ...

  (14 m)(12 m) -(12 m)(3 m) = (12 m)(14 -3) m = (12 m)(11 m) = 132 m^2

3 0
3 years ago
What is the number .2121 as a fraction
brilliants [131]
Are you being funny sayings 21
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3 years ago
How derivative of this absolute value function is like this!
Daniel [21]

Recall the definition of absolute value.

|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}

When x,

|x| = x \implies \dfrac{d|x|}{dx} = 1

When x,

|x| = -x \implies \dfrac{d|x|}{dx} = -1

The derivative does not exist at x=0, since the one-sided limits

\displaystyle \lim_{x\to0^-} f'(x) = -1

and

\displaystyle \lim_{x\to0^+} f'(x) = +1

do not match.

So the derivative of |x| is

\dfrac{d|x|}{dx} = \begin{cases} 1 & \text{if } x > 0 \\ -1 & \text{if } x < 0 \\ \text{undefined} & \text{if } x = 0\end{cases}

Now we can write this as

\dfrac{d|x|}{dx} = \dfrac x{|x|} = \dfrac{|x|}x

since

x > 0 \implies |x| = x \implies \dfrac{|x|}x = \dfrac xx = 1

and

x < 0 \implies |x| = -x \implies \dfrac{|x|}x = -\dfrac xx = -1

6 0
1 year ago
Madison is starting her own sewing business. Madison has calculated that she needs to earn $840 per week to support her family.
ArbitrLikvidat [17]

Answer:

$11.20 per hour

Explanation:

x = dollars per hour

75x = 840

x = 11.20

6 0
2 years ago
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