Okay so.
If lawn tickets are $30 and seat tickets are $50 and they sold 200 seat tickets.
50 multiplied by 200 is = $ 10,000
And the goal is $14,000.
So $14,000 subtract $10,000 is $4000
$4000 is how much they made in Lawn Tickets. In order to calculate how much lawn tickets were sold, is dividing $4000 by $30 since lawn tickets are $30.
4000 divided by $30 = 133
Not sure if this is correct but all the working and steps are correct! Hope this helps.
Answer:
i am positive it is x+y+z
Step-by-step explanation:
i'm so sorry if this is wrong..hope this helped :)
Answer:
$18,007,50
Step-by-step explanation:
First, you have to calculate the 85% of the base price that the dealer pays for the car:
base price: $18,750
$18,750*85%= $15,937.5
Second, you have to calculate the 75% of the installed options price that the dealer pays:
installed options price= $2,380
$2380*75%= $1,785
Third, you have to add the 85% of the base price plus the 75% of the installed options that the dealer has to pay and you also have to add the destination charge of $285:
$15,937.5+$1,785+$285= $18,007.5
According to this, the dealer has to pay $18,007.5 for the car with a base price of $18,750 and installed options price $2380 including a destination charge of $285.
Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:
<em>f(x) = 2(x - 3)^2 - 2</em>
<em></em>
Domain: (-∞, ∞)
Range: (-2, ∞)
X-intercepts: (4, 0), (2, 0)
Y-intercept: (0, 16)
Axis of Symmetry: x = 3
Minimum value (vertex): (3, -2)
Standard form: y = 2x^2 - 12x + 16
