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liberstina [14]
3 years ago
8

HELP!!!!!! Which of the following best completes the statement?

Mathematics
2 answers:
DerKrebs [107]3 years ago
8 0
B. Sometimes

Hope this helps!
Len [333]3 years ago
3 0
B 
they will be congruent if there is a pair of parallel lines
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Question #5
erastova [34]
X=9 how to solve: 72+48=8x+48
72=8x 8*9=72
4 0
3 years ago
What is the slope and equation of a line parallel to the y-axis passing through point (9, -1)?
mrs_skeptik [129]

Answer:

The slope is undefined and the equation of the line is x = 9 ⇒ C

Step-by-step explanation:

  • Parallel lines have the same slopes and different y-intercepts
  • The slope of any vertical line is undefined
  • The equation of any vertical line is x = a, where a is the x-coordinate of a point that lies on the line
  • All x-coordinates of the points lie on a vertical line equal

Let us solve the question

∵ The line is parallel to the y-axis

∵ The y-axis is a vertical line

→ By using the second note above

∴ The slope of the y-axis is undefined

→ By using the first note above

∴ The slope of the line is undefined

→ By using the third note above

∵ The equation of the vertical line is x = a

∵ a is the x-coordinate of a point on the line

∵ The line passes through the point (9, -1)

∴ a = 9

∴ The equation of the line is x = 9

4 0
3 years ago
The school department made $2,142 on ticket sales for 3 nights. Each ticket costs $7. How many tickets did they sell each night?
svetlana [45]

they sold 21 tickets each night
7 0
4 years ago
Assume that when adults with smartphones are randomly​ selected, 51​% use them in meetings or classes. If 11 adult smartphone us
Luba_88 [7]

Answer:

The probability is 0.2356.

Step-by-step explanation:

Let X is the event of using the smartphone in meetings or classes,

Given,

The probability of using the smartphone in meetings or classes, p = 51 % = 0.51,

So, the probability of not using smartphone in meetings or classes, q = 1 - p = 1 - 0.51 = 0.49,

Thus, the probability that fewer than 5 of them use their smartphones in meetings or classes.

P(X<5) = P(X=0) + P(X=1) + P(X=2) + P(X=3)+P(X=4)

Since, binomial distribution formula is,

P(x) = ^nC_r p^x q^{n-x}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

Here, n = 11,

Hence,  the probability that fewer than 5 of them use their smartphones in meetings or classes

=^{11}C_0 (0.5)^0 0.49^{11}+^{11}C_1 (0.5)^1 0.49^{10}+^{11}C_2 (0.5)^2 0.49^{9}+^{11}C_3 (0.5)^3 0.49^{8}+^{11}C_4 (0.5)^4 0.49^{7}

=(0.5)^0 0.49^{11}+11(0.5)0.49^{10} + 55(0.5)^2 0.49^{9}+165 (0.5)^3 0.49^{8} +330(0.5)^4 0.49^{7}

=0.235596671797

\approx 0.2356

4 0
4 years ago
If a school plans to spend $2,500 to serve 700 students, which statement is true?
AveGali [126]

Answer:

Company c will reach the goal

7 0
3 years ago
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