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Vikki [24]
3 years ago
13

40 thousands = _tens?

Mathematics
1 answer:
Yanka [14]3 years ago
5 0
40 thousands = 400 tens
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When flying at an altitude of 5 miles, the lines of sight to the horizon looking north and south make about a 173.7 degree angle
oksian1 [2.3K]
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles

Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
7 0
3 years ago
Write the expression<br> a2b3c2d in expanded<br> form.
Zanzabum

Answer:

a*2+b*2+c*2+d

Step-by-step explanation:

If i's meant to be Pythagorean theorem, a*a+b*b=c*c

8 0
3 years ago
I cant seem to understand this. please explain :))<br> (business math)
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Answer:

$1.50 bro

Step-by-step explanation:

4 0
3 years ago
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What type of transformation takes the graph of f(x)=|x| to the graph of g(x)=|4+x|?
ivolga24 [154]
Translation to the left by 4 units
4 0
3 years ago
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What is the value of x?
Nikolay [14]
Answer: 7 centimeters 

Explanation:

Let triangle ABC and triangle CDE form a bow tie such that 
     - triangle ABC is smaller than triangle CDE
     - Segment AC and segment CD are the north sides
     - Segment BC and segment CE are the bottom sides
     - AC = 6, CD = 42, CE = 36, BC = x

Since angle ACB and angle ECD are formed by intersecting segment AE and segment BD at point C, they are vertical angles. (See the attached picture) So, angle ACB and angle ECD are congruent. 

Moreover when we form our bowtie, point A is in the north side and point E is in the bottom sides and this implies that angle BAC and angle CED are alternate interior angles as shown in the attached figure. 

Since it is given in the problem that alternating interior angle are congruent, angle BAC and angle CED are congruent. 

Now, we have the following pairs of angles in triangle ABC and triangle CDE that are congruent:

- angle BAC and angle CED
- angle ACB and angle ECD

By AA Similarity theorem, when we have two pairs of congruent angles for two triangles, then the two triangles are similar. So, triangle ABC and triangle CDE are similar.

In similar triangles, the sides that are opposite to the congruent angles are proportional to each other. So, 

\frac{BC}{CD}  =  \frac{AC}{CE} &#10;&#10;&#10;    (1)

Since AC = 6, CD = 42, CE = 36, BC = x, we can substitute these values to equation (1). So, equation (1) becomes

\frac{x}{42} = \frac{6}{36}
\frac{x}{42} = \frac{1}{6}  (2)

SInce we are solving for x, we can multiply both sides of equation (2) by the denominator at the left side which is 42 so that

x = 42(1/6)
x = 7 centimeters

8 0
3 years ago
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