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FinnZ [79.3K]
3 years ago
5

Explain why when a strong acid is titrated with a strong base, the pH at equivalence pt. is equal 7, while in the case of a weak

acid (e.g., HC2H3O2) titrated with a strong base (NaOH) pH at equivalence point is above 7
Chemistry
1 answer:
goldenfox [79]3 years ago
5 0

Explanation:

The pH of a strong acid when titrated with a strong base is equal to 7 because of the formation of a neutral salt which corresponds to pH = 7.

But on the other hand,

The titration of the weak acid and strong base, the reaction taking place is:

HC₂H₃O₂  +  OH⁻  ⇒ H₂O  +  C₂H₃O₂⁻

At the equivalence point, the pH is greater than 7 because of the conjugate base formed in the above reaction which gives OH⁻ in the solution as:

C₂H₃O₂⁻ + H₂O ⇒ HC₂H₃O₂  +  OH⁻

<u>The hydroxide ions produced in the above reaction results in the pH above 7 (basic).</u>

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</span>
\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark

I hope this helps. =)
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