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Andreyy89
3 years ago
14

Can someone tell me how to do this! #2 & #4

Mathematics
2 answers:
torisob [31]3 years ago
8 0
2) The area is 1.1 m^2 because to find the area the formula is width*length. SO you would separate it. It would be 0.9 * 1 = 0.9 and 0.4 * 0.5 = 0.2. Then you add it together. So it would be 1.1 m^2. The perimeter is all the sides added together so 4.2 m, but it says mm so you have to convert it and you get 4200.
4) Area is 1.16 cm^2. Again you would seperate it. So, 1 * 1 = 1 and .2 * .8 = .16. Then you add it together and get 1.16 cm^2. The perimeter is all the sides added up. You get 4.2 cm. 
Studentka2010 [4]3 years ago
6 0
A= lxw
P=L+w+L+W
hope this helps ;)
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Please answer someone!!!
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topjm [15]

to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1.25})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-3.5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3.5}-\stackrel{y1}{(-1.25)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-1)}}}\implies \cfrac{-3.5+1.25}{8+1}\implies \cfrac{-2.25}{9}\implies -\cfrac{~~ \frac{225}{100}~~}{\frac{9}{1}} \\\\\\ -\cfrac{225}{100}\cdot \cfrac{1}{9}\implies -\cfrac{9}{4}\cdot \cfrac{1}{9}\implies -\cfrac{1}{4}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1.25)}=\stackrel{m}{-\cfrac{1}{4}}(x-\stackrel{x_1}{(-1)}) \\\\\\ y+1.25=-\cfrac{1}{4}(x+1)\implies y+\cfrac{5}{4}=-\cfrac{1}{4}x-\cfrac{1}{4} \\\\\\ y=-\cfrac{1}{4}x-\cfrac{1}{4}-\cfrac{5}{4}\implies y=-\cfrac{1}{4}x-\cfrac{6}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{2}

3 0
2 years ago
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MrMuchimi
Answers:
1. X= 0
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You can use this method to solve them step by step, hope it will help!

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