Question

Please help me with my Algebra homework!!!

Answer 1

Answer:

B) No Unique Solutions

Step-by-step explanation:

Given:

$z=x+5y-14$

$-2y=-4\\y={-4}{-2}=2$

$3x+y-3z=14$

now we now the value of y = 2 so we will substitute in equation  $z=x+5y-14$

$z=x+5\times2-14\\z=x+10-14\\z= x-4$

Now, We have value of y=2 and value of $z=x-4$ Substituting in both the value in equation $3x+y-3z=14$

$3x+2-3(x-4)=14\\3x+2-3x+12=14\\14=14$

which means that the equation has Infinite solutions.