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Mila [183]
3 years ago
11

Please help me with my Algebra homework!!!

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

B) No Unique Solutions

Step-by-step explanation:

Given:

z=x+5y-14

-2y=-4\\y={-4}{-2}=2

3x+y-3z=14

now we now the value of y = 2 so we will substitute in equation  z=x+5y-14

z=x+5\times2-14\\z=x+10-14\\z= x-4

Now, We have value of y=2 and value of z=x-4 Substituting in both the value in equation 3x+y-3z=14

3x+2-3(x-4)=14\\3x+2-3x+12=14\\14=14

which means that the equation has Infinite solutions.

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Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
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