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svetoff [14.1K]

3 years ago

9

Roger is a great pitcher. He strikes out 1 out of every 3 batters he faces. If he faces 18 batters in one game, about have many

would he probably strike out?

2 answers:

zepelin [54]3 years ago

7 0

He will strike out 6 batters in that game

pav-90 [236]3 years ago

7 0

He will strike out at least 6

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If you ride your bike 12 miles per hour, how long would it take<br> you to travel 72 miles ?

poizon [28]

Answer:

It would take 6 hours for you to travel 72 miles.

Step-by-step explanation:

This question can be solved by a simple rule of three.

We have that:

Each hour, you ride 12 miles.

How many hours will take for you to travel 72 miles?

So:

1 hour - 12 miles

x hours - 72 miles

12x = 72

x = 72/12

x = 6

It would take 6 hours for you to travel 72 miles.

4 0

3 years ago

What's 7/8 as a decimal?<br> a. 7.8<br> b. .875<br> c. 8.7<br> d. .78

OverLord2011 [107]

If you would like to write 7/8 as a decimal, you can do this using the following steps:

7/8 = (125*7)/1000 = 875/1000 = 0.875 = .875

The correct result would be b. .875.

5 0

3 years ago

Help me plz, i’d love u forever

Sergio039 [100]

1. We know that 1 feet = 12 inches

let x be a number of inches, which when added to 18 inches will give 7 feet

18 inches + x inches = 7 feet

18 inches + x inches = 84 inches <em> [1 feet = 12 inches]</em>

x inches = 84 inches - 18 inches

x inches = 66 inches

2. We know that 1 mile = 1760 yards

let x be the number of yards, when added to 2000 yards will be equal to 2 miles

2000 yards + x yards = 2 miles

2000 yards + x yards = 3520 yards

x yards = 1520 yards

3. We know that 1 feet = 12 inches

Number of feet = Given number of inches / 12

Number of feet = 108 / 12

Number of feet = 9 ft.

4. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 8800 feet. will be equal to 8 miles

8800 feet + x feet = 8 miles

8800 feet + x feet = 42240 feet <em>[1 mile = 5280 feet]</em>

x feet = 42240 - 8800

x feet = 33440 ft.

5. We know that 12 inches = 1 feet

let x be the number of inches, when added to 37 inches, will be equal to 5 feet

37 inches + x inches = 5 feet

37 inches + x inches = 60 inches <em> [12 inches = 1 feet]</em>

x inches = 23 inches

6. We know that 1 yard = 3 feet

So, (number of yards)*3 = (number of feet)

Number of yards = number of feet / 3

Number of yards = 73 / 3 = 24.33 yards

7. We know that 1 yard = 3 feet

let x be the number of feet added to 15 feet to make 9 yards

15 feet + x feet = 9 yards

15 feet + x feet = 27 feet <em>[1 yard = 3 feet]</em>

x feet = 12 ft

8. We know that 1 mile = 1760 yards

let x be the number of yards remaining to reach 4 miles

3000 yards + x yards = 4 miles

3000 yards + x yards = 7040

x yards = 4040 yards

9. We know that 1 yard = 3 feet

So, number of yards * 3 = number of feet

replacing the values:

number of yards*3 = 114

number of yards = 114/3

number of yards = 38 yards

10. We know that 1 mile = 5280 feet

let x be the number of feet that must be added to 9000 feet to make 3 miles

x feet + 9000 feet = 3 miles

x feet + 9000 feet = 15840 feet

x ft = 6840 ft

11. We know that 12 inches = 1 feet

let x be the number of inches that must be added to 46 inches to get a length of 9 feet

46 inches + x inches = 9 feet

46 inches + x inches = 108 inches

x inches = 108 - 46 inches

x inches = 62 inches

12. We know that 1 mile = 1760 yards

let x be the number of yards that must be added to 3500 yards to make 2 miles

3500 yards + x yards = 2 miles

3500 yards + x yards = 3520 yards

x = 20 yards

13. We know that 1 ft = 12 inches

So, number of feet * 12 = number of inches

number of feet = number of inches / 12

<em>number of feet in 252 inches</em>

Number of feet = 252/12

Number of feet = 21 ft

14. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 6500 feet, will be equal to 2 miles

x ft + 6500 ft = 2 miles

x ft + 6500 ft = 10560 ft

x ft = 4060 ft

15. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 4500 feet, will be equal to 1 mile

x ft + 4500 ft = 1 mile

x ft + 4500 ft = 5280 ft

x ft = 780 ft

3 0

3 years ago

Add: (7-5i) (-10+2i)

Mice21 [21]

Answer:

-10i^(2) + 64i - 70

5 0

3 years ago

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

3 years ago