1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firdavs [7]
3 years ago
9

**WILL GIVE BRAINLIEST** PLZ HELP ASAP!!

Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0
Length: 2w-12
Area is length times width so (2w-12)*w
Or 2w^w-12w
You might be interested in
The total of p,t and d
frosja888 [35]

Answer:

what does that mean

Step-by-step explanation:

6 0
3 years ago
Find the derivative of<br> <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B6%7D%7Bx%7D%20" id="TexFormula1" titl
aev [14]
f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}
8 0
3 years ago
A boy who is 1.8 meters tall stands 1 meter away from a lamppost and casts a shadow 2 meters long. The height of the lamppost is
DaniilM [7]
2.7 is the height of the lamppost in meters.

7 0
3 years ago
Read 2 more answers
Prove that if the set of vectors {u1, u2, u3} is linearly dependent and u4 is any vector, then the set {u1, u2, u3, u4} is linea
Lesechka [4]

Answer with Step-by-step explanation:

We are given that the set of vectors{u_1,u_2,u_3} is lineraly dependent set .

We have to prove that the set {u_1,u_2,u_3,u_4} is linearly dependent .

Linearly dependent vectors : If the vectors u_1,u_2.u_3,u_4

are linearly  dependent therefore the linear combination

a_1u_1+a_2u_2+a_3u_3+a_4u_4=0

Then ,there exit a scalar which is not equal to zero .

Let a_1\neq0 then the vector u_1 will be zero and remaining  other vectors are not zero.

Proof:

When u_1,u_2,u_3 are linearly dependent vectors therefore, linear combination of vectors of given set

a_1u_1+a_2u_2+a_3u_3=0

By definition of linearly dependent vector

There exist a scalar which is not equal to zero.

Suppose a_1\neq 0 then  u_1=0

The linear combination of the set {u_1,u_2,u_3,u_4}

a_1u_1+a_2u_2+a_3u_3+a_4u_4=0

When a_1\neq0\; and\; u_1=0

Therefore,the set {u_1,u_2,u_3,u_4} is linearly dependent because it contain a vector which is zero.

Hence, proved .

5 0
3 years ago
How much does 6.1 cubic feet of water weigh in pounds
Dovator [93]

Answer:

380.832 pounds    Approximately

Step-by-step explanation:

1 foot of water = 62.428 pounds  (62.43)

6.1* 62.43= 380.832

6 0
3 years ago
Other questions:
  • Find the length of  if AB = 8 and CB = 4
    10·1 answer
  • In radical form simplify, the squareroot of 300
    9·1 answer
  • If a+b=1, find N=a^3+b^3+3ab
    12·2 answers
  • Which expressions are equivalent to the one below? CHECK ALL THAT APPLY
    11·1 answer
  • What is the total volume?
    14·1 answer
  • Please help it's due right now
    7·2 answers
  • Simplify<br> 43 +4.5<br> Plzzz help!!!!!!
    12·2 answers
  • Twins Isaac and Isaiah were just born. Isaac weighs 6666 pounds 2222 ounces and Isaiah weighs 5555 pounds 4444 ounces.
    5·2 answers
  • Which product is greater than 3/4
    12·2 answers
  • If x=25 when y=15, find x when y=24
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!