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bonufazy [111]
2 years ago
14

The book store is having a sale on bookmarks. Each bookmark is on sale for $0.84. Each student in Ms. Duke's class decides to bu

y a bookmark. There are 23
students in Ms. Duke's class. How much will the class spend on bookmarks at the book store?
Mathematics
1 answer:
Natali [406]2 years ago
4 0
The class will spend 19.32 on bookmarks
$0.84 x 23 = 19.32
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Which number line best represents the solutions to 7 &lt; -2x + 3?
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1 year ago
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
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QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

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f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

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QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

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Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
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x-y=\frac{4}{2}

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Adding (1) & (2)

2x=12

x=6

Substituting in (1) we get

y=4

7 0
3 years ago
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