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bonufazy [111]
3 years ago
14

The book store is having a sale on bookmarks. Each bookmark is on sale for $0.84. Each student in Ms. Duke's class decides to bu

y a bookmark. There are 23
students in Ms. Duke's class. How much will the class spend on bookmarks at the book store?
Mathematics
1 answer:
Natali [406]3 years ago
4 0
The class will spend 19.32 on bookmarks
$0.84 x 23 = 19.32
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2 years ago
In 2000, the average monthly price for basic cable television in the United States was $29.99. In 2016, the average monthly pric
Lelu [443]

Answer:

y(x) = 29.99 + 1.86x

The cost of basic cable television in the United States in the year 2020 will be $67.19.

Step-by-step explanation:

The linear function has the following format.

y(x) = y(0) + ax

In which y(x) is the cost x years after 2000, y(0) is the initial cost, that is, the cost in 2000, and a is the slope(how much the cost changes in a year).

In 2000, the average monthly price for basic cable television in the United States was $29.99.

This means that y(0) = 29.99

In 2016, the average monthly price for the same basic cable television was $59.75.

2016 is 16 years after 2000. So

y(16) = 59.75

Write a linear function that models the cost of basic cable television in the United States for x years after 2000.

y(x) = y(0) + ax

Applying y(16).

59.75 = 29.99 + 16a

16a = 29.76

a = \frac{29.76}{16}

a = 1.86

So

y(x) = 29.99 + 1.86x

Use the linear function to determine the cost of basic cable television in the United States in the year 2020.

2020 is 20 years after 2000, so this is y(20).

y(x) = 29.99 + 1.86x

y(20) = 29.99 + 1.86*20 = 67.19

The cost of basic cable television in the United States in the year 2020 will be $67.19.

3 0
3 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C

Solve for x(t).

\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}

3 0
2 years ago
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