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lubasha [3.4K]
3 years ago
12

Olivia is placing a gift inside a box that measures 15 centimeters by 8 centimeters by 3 centimeters. What is the surface area o

f the box? A. 378 square centimeters B. 288 square centimeters C. 189 square centimeters D. 26 square centimeters

Mathematics
2 answers:
kotegsom [21]3 years ago
7 0
The answer is A 
hope this helps.
Shalnov [3]3 years ago
4 0
The answer would be A, 378 square centimeters.
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Yuliya22 [10]
The sum of 8 times a number and 7.....sum means add
8n + 7

is twice the number...is means equals
= 2n

so we have : 8n + 7 = 2n
7 0
4 years ago
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7-4[3-(4y-5)] plz help me
ad-work [718]

Let's simplify step-by-step. <span>7−<span>4<span>(<span>3−<span>(<span><span>4y</span>−5</span>)</span></span>)</span></span></span>

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<span><span /></span>Combine Like Terms: <span>=<span><span><span>7+<span>−12</span></span>+<span>16y</span></span>+<span>−20</span></span></span><span>=<span><span>(<span>16y</span>)</span>+<span>(<span><span>7+<span>−12</span></span>+<span>−20</span></span>)</span></span></span><span>=<span><span>16y</span>+<span>−25</span></span></span>

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<span><span><span /></span></span>Answer: <span>=<span><span>16y</span>−<span>25</span></span></span>

7 0
3 years ago
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Can you show us how to find the discriminant of the quadratic x^2 + 2x -2 =0
lorasvet [3.4K]
<em>Step #1: </em>
Make sure the equation is in the form of [ Ax² + Bx + C = 0 ].

Yours is already in that form.
A = 1
B = 2
C = -2

<em>Step #2:</em>
The 'discriminant' for that equation is [ B² - 4 A C ].
That's all there is to it, but it can tell you a lot about the roots of the equation.

-- If the discriminant is zero, then the left  side of the equation is a perfect square,
and both roots are equal. 

-- If the discriminant is greater than zero, the the roots are real and not equal.

-- If the discriminant is less than zero, then the roots are complex numbers.

The discriminant of your equation is  [ B² - 4 A C ] = 2² - 4(1)(-2) = 4 + 8 = 12

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3 years ago
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HELP ASAP
zavuch27 [327]
2rd one I could be wrong tho
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