An air traffic controller is tracking two planes. To start, Plane A was at an altitude of890 meters, and Plane B was at an altitude of1322 meters. Plane A is losing altitude at 16 meters per second, and Plane B is losing altitude at25 meters per second. Expression which shows altitude of plane after x seconds.
Equation to show when they'll both be at the same altitude
Answer:
890 - 16x ; 1322 - 25x ; 9x = 432 = x = 48
Step-by-step explanation:
Plane A:
Altitude = 890 m
Altitude loss = 16 m per second
Plane A:
Altitude = 1322 m
Altitude loss = 25 m per second
Equation :
Altitude - (altitude loss * time)
Plane A:
890 - 16x
Plane B:
1322 - 25x
Plane A = Plane B
890 - 16x = 1322 - 25x
-16x + 25x = 1322 - 890
9x = 432
x = 432 / 9
x = 48 seconds
