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Lynna [10]
3 years ago
11

Solve for x -6x + 14<-28 AND 3x + 28 < 25

Mathematics
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

Treat the lesser than sign as an equal sign. What you do to one side, you do to the other. Isolate the variable x. Do the opposite of PEMDAS.

PEMDAS = Parenthesis, Exponents ( & roots), Multiplication, Division, Addition, Subtraction.

<u>Solve -6x + 14 < -28</u>

First, subtract 14 from both sides:

-6x + 14 (-14) < -28 (-14)

-6x < -42

Next, divide -6 from both sides to isolate the variable x. Note that when you divide (or multiply) by a negative number, you must flip the greater than or less than sign.

(-6x)/-6 < (-42)/-6

x > (-42)/(-6)

x > 7

x > 7 is your answer.

<u>Solve 3x + 28 < 25</u>

First, subtract 28 from both sides.

3x + 28 (-28) < 25 (-28)

3x < -3

Isolate the variable x. Divide 3 from both sides. Note that because you aren't dividing by a negative number (rather a positive 3), you do not flip the sign.

(3x)/3 < (-3)/3

x < (-3)/(3)

x < -1

x < -1 is your answer.

~

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