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Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
Answer:
2.
x=3 y=3
Step-by-step explanation:
3-3=0
3+3=6
If 3x-3y equals 0, then what's x+y. It concluded to 6
9514 1404 393
Answer:
x^(1/6)
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)/(a^c) = a^(b-c)
__
Here, we have a=X, b=1/2, c=1/3, so the quotient is ...
(X^(1/2))/(X^(1/3)) = X^(1/2 -1/3) = X^(1/6)
_____
Expressed as a radical, this is ...
![\displaystyle X^{\frac{1}{6}}=\sqrt[6]{X}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20X%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%3D%5Csqrt%5B6%5D%7BX%7D)
