All categories

3 years ago

What are the solutions of the quadratic equation x2-8x+12=0?

Mathematics

1 answer:

aleksley [76]3 years ago

7 0

Answer:

X^2-8x+12=0

(X-6)(X-2)

X-6=0 X-2=0

X=6 X=2

You might be interested in

Determine the intercepts of the line.<br> y-intercept (____,____)<br> x-intercept (____,____)

bija089 [108]

Answer:

y intercept is (0 , 2.5)

x intercept is (3.5 , 0)

Step-by-step explanation:

Khan Academy is fun !!!!!!!!!!

y- intercept is where the line meets the y line l

x- intercept is where the line meets the x line ____

The y-intercept is 2.5

The x-intercept is 3.5

3 0

2 years ago

A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h , of the basketbal

noname [10]

Answer:

$\boxed {\boxed {\sf 7.5 \ feet}}$

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

$h=-16t^2+25t+6$

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

$h= -16(1.5)^2+25(1.5)+6$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

(1.5)²= 1.5*1.5=2.25

$h= -16(2.25)+25(1.5)+6$

Multiply.

$h= -36+25(1.5)+6$

$h= -36+37.5+6$

Add.

$h=1.5+6=7.5$

This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

6 0

2 years ago

AHH HELP ME AGAIN :P THERES ONE MORE AFTER THIS

mihalych1998 [28]

Answer:

26.25

Step-by-step explanation:

y = 8.75(3)

y = 26.25

6 0

2 years ago

Read 2 more answers

May someone help me with this question

Dafna11 [192]

X + 13 = -4
x = -4 - 13
x = - 17
I am thinking it is the first one..solution is -17

3 0

2 years ago

Use the function g(x)-x+2 with initial values of 4, 2, and 1. What happens

kolezko [41]

Answer:

Step-by-step explanation:

The given function is , g(x)= - x + 2

For values of , is the sequence, -2,4,-2,4,-2,4........

For values of , is the sequence, 0,2,0,2........

For values of , is the sequence, 1,1,1,1,........

For initial value, of 4,the sequence converges to two values that is -2, 4.

For initial value of 2, the sequence again converges to two values which are 0,2.

For initial value of 1, the sequence converges to one value which is 1.

→→First Iterative value that is (-2)=Second iterative value (0) + 2 ×Third iterative value(1)

→→ First Iterative value that is (4)=Second iterative value (2) + 2 ×Third iterative value(1)

4 0

3 years ago