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luda_lava [24]
3 years ago
8

Three ways to write a division problem

Mathematics
2 answers:
8090 [49]3 years ago
6 0
My three examples would be, 15/3, 15 then the divided by sign 3. 15 over 3 too. Hope this helps!!!
marin [14]3 years ago
3 0
1/1
3./.3
6(and the box thing that has a live over the nombers)4
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What is the algebraic expression for the difference between nine times a number and four more than six times the number?
Mazyrski [523]

Answer:

9n-(6n+4)

Step-by-step explanation:

n is number

7 0
3 years ago
Double checking to see if i'm right!
Vinvika [58]

Answer:

Yep! That looks right!

Step-by-step explanation:

4 0
2 years ago
What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2
NARA [144]

Given:

The inequalities are:

-2

-2\leq x

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

-2

-2\leq x

For -2, the possible integer values are

x=-1,0,1,2          ...(i)

For -2\leq x, the possible integer values are

x=-2,-1,0,1        ...(ii)

The common values of x in (i) and (ii) are

x=-1,0,1

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

6 0
2 years ago
HELPP, Lines parallel, Perpendicular, Neither? URGENT HELPPP.
VLD [36.1K]

Answer:

perpendicular I believe

Step-by-step explanation:

I'd plot the points and make a line using a ruler to check though.

8 0
2 years ago
What the answer to this question
Sonja [21]

To solve this, you need to isolate/get the variable "u" by itself in the inequality:            u = unknown number

2u - 3 < 1       Add 3 on both sides

2u - 3 + 3 < 1 + 3

2u < 4        Divide 2 on both sides to get "u" by itself

u < 2       (u is any number less than 2)

When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.

When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.

u < 2        

Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.

3 0
3 years ago
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