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4 years ago

What is 1/2 X 3 Plus 1/2 Plus 1/2 Plus 1 ?

Mathematics

2 answers:

Reptile [31]4 years ago

8 0

The answer would be 3.5.

miss Akunina [59]4 years ago

5 0

The answer would be 3 1/2 or 3.5

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Select ALL the correct answers.

just olya [345]

The "9" in the second term is a coefficient.

5 0

3 years ago

Is p = 3 a solution to this equation? 4 p = 24

Blizzard [7]

Answer:

Hi there!

Your answer is:

No, p= 3 is <u>not</u> a solution for this equation!

Step-by-step explanation:

4(3) = 24 ???

4×3 = 24?

12 = 24??

NO. 12 does <u>NOT</u> equal 24!

Hope this helps

7 0

3 years ago

What linear function represents the line given by the point slope equation y+7= 2/3(x+6)?

aleksandrvk [35]

Answer:

The graph of the line in the attached figure

Step-by-step explanation:

we have

$y+7=\frac{2}{3}(x+6)$

This is the equation of a line into point slope form

The slope is $m=\frac{2}{3}$

The line pass through the point (-6,-7)

To graph the line find the y-intercept

Remember that

The y-intercept of the line is the value of y when the value of x is equal to zero

For x=0

$y+7=\frac{2}{3}(0+6)$

$y+7=\frac{2}{3}(6)$

$y+7=4$

$y=4-7=-3$

The y-intercept is the point (0,-3)

with the point (-6,-7) and (0,-3) plot the line

see the attached figure

8 0

3 years ago

A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

8 0

4 years ago

Help please)))))))))))))))))))

timurjin [86]

The giraffe (using the ruler) is 11 cm.

1 cm : 50 cm

Multiply both sides by 11.

11 cm : 550 cm

There are 0.01 meters in 1 centimeter.

Multiply 550 cm by 0.01.

(550)(0.01) = 5.5

The giraffe's real length is 5.5 meters.

5 0

3 years ago