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Veseljchak [2.6K]
3 years ago
6

What do customers use to access the internet, usually for a monthly fee?

Computers and Technology
1 answer:
kati45 [8]3 years ago
4 0
To search things like answers,order things on Amazon,or go watch videos on Youtube
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Consider two sets S1 and S2 of size 3 and 2 each.
Brrunno [24]

Answer:

Answered

Explanation:

function from S_1 to S_2 (functions have unique mapping

each element in S_1 has 2 elements to map to in S_2 and there are 3 elements in S_1

therefore number of functions = 2^3 = 8 (2 choices for each of 3 elements)

a) relations between S_1 and S_2 are subset of S_1 x S_2

there are 6 elements in S_1 x S_2 therefore relations would be 2^6 = 64

(no of subsets of set of n elements = 2^n)

b) By above explanation functions from S_2 to S_1 = 3^2 = 9

 and relation from S_2 to S_2 = 2^4 = 16

7 0
3 years ago
1.
Brums [2.3K]

Answer:

as

is so good

Explanation:

7 0
2 years ago
Describe a situation in which a robot may have to avoid an obstacle without coming to a complete stop before turning.
Airida [17]

A robot may have to avoid an obstacle without coming to a complete stop before turning. If the robot is able to make a wide enough, long turn. instead of stopping, then turning sharply. For example if the robot were to come across an object and can sense said object before hand. it can then take action into turning before it is close enough.

3 0
2 years ago
Read 2 more answers
Which of the following is not a good technique for photographing groups? Visiting the location.
algol13
I think it's wait until you get started to decide on the props and camera settings...
4 0
2 years ago
Write a program which asks the user to enter N numbers. The program will print out their average. Try your program with the foll
Likurg_2 [28]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

int n;

double average,sum=0,x;

cout<<"enter the Value of N:";

// read the value of N

cin>>n;

cout<<"enter "<<n<<" Numbers:";

// read n Numbers

for(int a=0;a<n;a++)

{

   cin>>x;

   // calculate total sum of all numbers

   sum=sum+x;

}

// calculate average

average=sum/n;

// print average

cout<<"average of "<<n<<" Numbers is: "<<average<<endl;

return 0;

}

Explanation:

Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.

Output:

enter the Value of N:5

enter 5 Numbers:20.5 19.7 21.3 18.6 22.1

average of 5 Numbers is: 20.44

7 0
3 years ago
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