Ask question

Ask question

All categories

igor_vitrenko [27]

3 years ago

8

Find the area and perimeter of the shape below. Help plzzz.

1 answer:

kozerog [31]3 years ago

4 0

Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²

You might be interested in

PLEASE HELP, i will give BRAINLIEST to the best answer.

sveticcg [70]

Answer: x 50 y 5

Step-by-step explanation: In the graph

4 0

2 years ago

Read 2 more answers

Simplify 4radical2plus7radical2minus3radical2

zlopas [31]

Let "radical 2" be represented by "r."

Then you are to simplify 4r + 7r - 3r. This comes out to 11r - 3r = 8r.

The answer is 8 radical 2.

3 0

2 years ago

PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK

Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
∠KLM = 58.24313614°

$\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)$

$\implies \textsf{Arc length MK}=\sf 15.45132428\:units$

6 0

1 year ago

HELPP<br> find the area of the shaded figure

Aliun [14]

Answer:

24 because 8×3. .................

5 0

2 years ago

Question 3 (10 points)

arlik [135]

Answer:

7.96 × 10⁸ kg

Step-by-step explanation:

Step 1: Given data

Mass of the Eiffel Tower (mE): 9.16 × 10⁶ kg

Mass of the Golden Gate Bridge (mG): 8.05 × 10⁸ kg

Step 2: Determine how many more kilograms is the mass of the Golden Gate Bridge than the mass of the Eiffel Tower

To determine this ratio, we need to do the following subtraction.

mG - mE = 8.05 × 10⁸ kg - 9.16 × 10⁶ kg = 7.96 × 10⁸ kg

The Golden Gate Bridge has approximately 7.96 × 10⁸ kg more than the Eiffel Tower.

6 0

2 years ago

Read 2 more answers