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Tpy6a [65]
3 years ago
10

Write the slope intercept form of the line that travels through (4,-1) and is parallel to y=1/4x

Mathematics
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

\boxed {\boxed {\sf y=\frac {1}{4}x-2}}

Step-by-step explanation:

Since we are given a point and a slope, we can use the point-slope formula.

y-y_1=m(x-x_1)

where m is the slope and (x₁ , y₁) is the point the line passes through.

We know the point is (4, -1).

We have to find the slope. We know that the line is parallel to y=1/4x.

This line has a slope of 1/4 (1/4 is the coefficient of x), and parallel lines have the same slope. Therefore, the line we are finding also has a slope of 1/4.

So, we know that:

  • m=1/4
  • x₁= 4
  • y₁= -1

Substitute these values into the formula.

y--1=\frac{1}{4}(x-4)

Now we must put the equation into slope-intercept form, or y=mx+b. We have to isolate y on one side of the equation.

First, distribute the 1/4. Multiply each term inside the parentheses by 1/4.

y--1=(\frac {1}{4}*x )+(\frac{1}{4} * -4)\\y+1= \frac {1}{4}x-1

1 is being added to y. The inverse of addition is subtraction, so subtract 1 from both sides of the equation. This will leave the variable y by itself.

y+1-1= \frac {1}{4}x-1-1

y=\frac {1}{4}x-1-1\\y=\frac {1}{4}x-2

The equation of the line is <u>y=1/4x-2</u>

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Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

x is quantity sold.

Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

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