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3 years ago

3(3y-4)=33 plz answer

Mathematics

2 answers:

zloy xaker [14]3 years ago

6 0

Answer:

y = 5

Step-by-step explanation:

First you need to distribute.

3(3y - 4) = 33

9y - 12 = 33

Then add 12 to both sides.

9y = 45

Now, divide both sides by 9.

Y = 5

Readme [11.4K]3 years ago

4 0

Answer:

y=5

Step-by-step explanation:

3(3y-4)=33

9y-12=33

9y=45

y=5

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In right triangle DEF, ∠E is a right angle, m∠D=26∘, and DF=4.5.

jok3333 [9.3K]

Answer:

The measurement of EF is 1.98 units

Step-by-step explanation:

In Δ DEF

∵ m∠E = 90°

∴ FD is the hypotenuse of the triangle

∵ m∠D = 26°

∵ EF is opposite to angle D

- We can use the sine ratio to find it

∵ sin D = $\frac{EF}{FD}$ ⇒ (opposite side / hypotenuse)

∵ FD = 4.5 units

∴ sin(26) = $\frac{EF}{4.5}$

- Multiply both sides by 4.5

∴ 4.5 sin(26) = EF

∵ sin 26° ≈ 0.44

∴ 4.5(0.44) = EF

∴ 1.98 = EF

The measurement of EF is 1.98 units

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3 years ago

The radius of a circle is 3 cm what is the circumference

malfutka [58]

the circumference is about 18.85

6 0

3 years ago

A car was Skid to a half a uniform rate of -9.4 m/s ^2 squared if the measure skid marks that are 34 m long with what speed is t

babymother [125]

Answer:

vi = 25.28 m/s

Step-by-step explanation:

a = -9.4 m/s²

x = 34 m

vf = 0 m/s

vi = ?

We can apply the equation

vf² = vi² + 2*a*x

⇒ vi = √(vf² - 2*a*x)

⇒ vi = √((0 m/s)² - 2*(-9.4 m/s²)*34 m)

⇒ vi = 25.28 m/s

5 0

3 years ago

If DE + EF = DF, and ____________, then the point E is the midpoint of .

gogolik [260]

<span>DE=EF hope I helped with your studies :)

</span>

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3 years ago

A group of students volunteered to finish a task in 25 days .1 Q of students did not come n the work could b completed in 35 day

SpyIntel [72]

Answer:

p=7Q/2

Step-by-step explanation:

Original number of students:

p students to do 1 job in 25 days.

Let r= the rate for 1 student.

pr*25=1

pr*25=1 is the work rate equation for p students.

Lesser number of students:

p-Q students came to do the job and time required was 35 days.

(P-Q)*r*35=1.

The unknowns are p, Q and r

Equate the original number of students and the lesser number of students

pr*25=(P-Q)*r*35

25rp=35rp - 35Qr

Collect like terms

25rp-35rp = -35Qr

Divide both sides by -5

-5rp+7rp=- 7rp

It can be re written as

7rp-5rp=-7Qr

2rp=7Qr

Make p the subject of the formula

p=7Qr/2r

p=7Q/2

p=7Q/2 is the original number of students

-10rp = -35Qr

The system of these two equations can be solved for p. See the THREE unknown

variables, p, r, and Q. You might assume that either r or Q would be a constant.

5 0

3 years ago