1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
10

About 400,000 people visited an art museum in December. What could be the exact number of people who visited the art museum

Mathematics
2 answers:
Zigmanuir [339]3 years ago
8 0
The answer is 359,572
maneilsocool10
2 years ago
it is 359,572
slega [8]3 years ago
3 0

Answer:

From 350,000 to 449,000

Step-by-step explanation:

Here, the given number,

400,000

Since, a number is rounded to 400,000 if it is between 350,000 to 449,000 including 350,000 and 449,000

Because, a number having 3 in hundred thousand place is rounded to 400,000, if the ten thousand digit of the number is 5 or more than 5,

Also, a number having 4 in hundred thousand place is rounded to 400,000, if the ten thousand digit of the number is less than 5,

Hence, the possible exact number of people who visited the art museum would be,

From 350,000 to 449,000

maneilsocool10
2 years ago
it is 359,572
You might be interested in
When consumers apply for credit, their credit is rated using FICO (Fair, Isaac, and Company) scores. Credit ratings are given be
Flura [38]

Answer:

a) The 99% confidence interval would be given by (589.588;731.038)

b) If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

661 595 548 730 791 678 672 491 492 583 762 624 769 729 734 706

Part a

Compute the sample mean and sample standard deviation.  

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n}  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}  

=AVERAGE(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

On this case the average is \bar X= 660.313

=STDEV.S(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

The sample standard deviation obtained was s=95.898

Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =16<30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. The degrees of freedom are given by:

df=n-1=16-1=15

We can find the critical values in excel using the following formulas:

"=T.INV(0.005,15)" for t_{\alpha/2}=-2.95

"=T.INV(1-0.005,15)" for t_{1-\alpha/2}=2.95

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}  

And if we find the limits we got:

660.313- 2.95\frac{95.898}{\sqrt{16}}=589.588  

[tex]660.313+ 2.95\frac{95.898}{\sqrt{16}}=731.038/tex]  

So the 99% confidence interval would be given by (589.588;731.038)

Part b

If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

4 0
2 years ago
To make iced tea, 5 tea bags can be added to 1 gallon of water. Find how many bags can be used for 4 gallons of water
Nata [24]

Answer:

20 tea bags

Step-by-step explanation:

if 5 is 1 gallon then you do 5x4=20

4 0
3 years ago
WILL MARK BRAINLIEST CAR!!!! HELP
Digiron [165]

Answer:

111°

Step-by-step explanation:

Let the centre of the circle be C

mRQ=157 (marked)

The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92

All the arc measure add up to 360 so:

mSQ+mRQ+mSR=360

mSQ+157+92=360

mSQ=360-249=111

4 0
3 years ago
One day , the tempeture ranged from a high of 20 degrease to a low of -25F. By how many degrees did the tempeture change?
Llana [10]
The temperature changed 45 degrees
7 0
3 years ago
Help me i’ll mark as brainliest
Andrei [34K]
The measure of the unknown angle should be 110 degrees. the measure of the angles have a sum of 180 degrees. the angles make up a 180 degree angle
8 0
3 years ago
Other questions:
  • LeAnn wants to giftwrap a present she got for her little brother. How many square inches of giftwrap will be needed to cover a b
    6·1 answer
  • A volleyball curt is 61 feet lenght and 21 feet wide. How much rope will you use to mark the outline on the court?
    13·1 answer
  • Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the g
    13·2 answers
  • Which of the following cosine functions has a period of 3 π ?
    10·2 answers
  • -4 (w+1) -24 Please help guys!
    12·2 answers
  • Hmm, which ones true?
    12·2 answers
  • Is 3abc an expression?
    12·2 answers
  • I can’t think rn can someone pls help?
    6·1 answer
  • Increase 56 in ratio 2:3
    7·2 answers
  • What is the value of F(x)=-x+9 if x=-7
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!