Question

Plss help!Question: Find a,b and c​

Answer 1

Answer:

See below, please

Step-by-step explanation:

The right：

${(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba =$

$= {y}^{2} - bx + 2cy + {c}^{2} - ab$

The left:

$= {y}^{2} - 7x - 18y + 109$

So, after comparing the right side and the left side of this equation, we know

1)

$b = 7$

2)

$2c = - 18 \\ so \\ c = - 9$

3)

${c}^{2} - ab = 109$

So,

$a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4$