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Iteru [2.4K]
2 years ago
10

Plss help!Question: Find a,b and c​

Mathematics
1 answer:
Roman55 [17]2 years ago
6 0

Answer:

See below, please

Step-by-step explanation:

The right:

{(y + c)}^{2}  - b \times (x + a) \\  = ( {y}^{2}  + 2yc +  {c}^{2} ) - bx - ba  =

= {y}^{2}  - bx + 2cy +  {c}^{2}  - ab

The left:

=  {y}^{2}  - 7x - 18y + 109

So, after comparing the right side and the left side of this equation, we know

1)

b = 7

2)

2c =  - 18 \\ so \\ c =  - 9

3)

{c}^{2}  - ab = 109

So,

a =  \frac{ {c}^{2}  - 109}{b}  =  \frac{ { (- 9)}^{2}  - 109}{7}  =  \frac{ - 28}{7}  =  - 4

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Warmup/Reflection- necessary for attendance
Pepsi [2]

Answer:

x = 7

Step-by-step explanation:

-3 + 2x = 11

(group like terms)

2x = 11 + 3

2x = 14

(divide both sides by 2 to make x stand alone)

2x/2 = 14/2

x = 7

8 0
3 years ago
Solve this polynomial expression please.
Sedbober [7]
-9x^3 +54x^2 -30x +12
5 0
2 years ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
1 year ago
If f(x)= x^-2, and g(x)=3x-1 whats the domain of f(g(x))?
andrey2020 [161]
4 and 7 and 8 and 9 and10
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7Bz%7D%7B4%7D%20%2B30%29%20%2B%20%28%5Cfrac%7Bz%7D%7B2%7D%20%29%20%3D%20180" id="Te
Dovator [93]

Answer:

  x = 200

Step-by-step explanation:

Multiply by 4:

  x + 120 + 2x = 720

  3x = 600 . . . . . . collect terms, subtract 120

  x = 200 . . . . . . . divide by 3

_____

<em>Check</em>

  (200/4 +30) +(200/2) = 180

  (50 +30) + 100 = 180

  80 + 100 = 180 . . . . . true

_____ _____

<em>Alternate solution</em>

If you like, you can simply work with the equation given.

  (3/4)x + 30 = 180 . . . . collect terms

  (3/4)x = 150 . . . . . . . . . subtract 30

  x = 200 . . . . . . . . . . . . multiply by 4/3

4 0
3 years ago
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