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olga_2 [115]
3 years ago
8

A sequence can be generated by using an=4a(n-1)

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0
This problem is half understanding the question and half just plugging in numbers.

Understanding the Question:
So its saying that n = whole number bigger than one, making n = 2, 3, 4, 5, etc.

Now try plugging any number n into the a_n = 4a_{n-1} equation. Let's use 2 to make it simple. If you plug in 2, you get:
a_2 = 4a_{2-1}\\
a_2 = 4a_1
Remember that the subscripts (the small numbers in the corner) are simply the term number. a_1 is term 1, a_2 is term 2, etc. The equation is saying that "term 2 = 4 times term 1."

If you keep plugging in random numbers for n, you'll see that the equation basically says, "a term = 4 times the term right before it." That makes it easy to plug and chug to get our answer.

Plugging and Chugging
Now we understand the question is asking for the first 4 terms, and each term is 4 times the last term. You're told that term 1, a_1 = 6. That makes the next four terms:

Term 2
a_2 = 4a_{2-1}\\
 a_2 = 4a_1\\
 a_2 = 4(6)\\
 a_2 = 24

Term 3
a_3 = 4a_{3-1}\\ a_3 = 4a_2\\ a_3 = 4(24)\\ a_3 = 96

Term 4
a_4 = 4a_{4-1}\\ a_4 = 4a_3\\ a_4 = 4(96)\\ a_4 = 384

Your first 4 terms are 4, 24, 96, and 384.

--------

Answer: A) F

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Mandarinka [93]

Answer:

<h2>x = 3.1</h2>

Step-by-step explanation:

<h3>{10}^{x}  = 1200</h3>

<u>To solve first take logarithm to both sides</u>

That's

<h3>log_{10}(10) ^{x}  =  log_{10}(1200)</h3><h3 /><h3>log_{10}(10)^{x}  = x log_{10}(10)</h3>

But

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So we have

x =  log_{10}(1200)

<u>Write 1200 as a number with the factor 100</u>

That's

1200 = 100 × 12

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<h3>x =  log_{10}(100 \times 12)</h3>

<u>Using the rules of logarithms</u>

That's

<h3>log_{a}(x \times y)  =  log_{a}(x)  +  log_{a}(y)</h3>

Rewrite the expression

That's

<h3>x =  log_{10}(100)  +  log_{10}(12)</h3><h3 /><h3>x =  log_{10}(10)^{2}  +  log_{10}(12)</h3><h3>x = 2 log_{10}(10)  +  log_{10}(12)</h3><h3>log_{10}(10)  = 1</h3><h3 /><h3>x = 2 +  log_{10}(12)</h3>

x = 3.079

So we have the final answer as

<h3>x = 3.1 to one decimal place</h3>

Hope this helps you

8 0
3 years ago
In Argentina, a cow on a ranch is expected to need an average of 4200 m2
nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

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Then, for 4500 cows:

4500 \: cows = 4200 \:  {m}^{2}  \times 4500

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Then let the area of the field be x in hectares:

1 \: hectare = 10000 \:  {m}^{2}

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x =  \boxed{ 1890 \: hectares}

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Step-by-step explanation:

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Montano1993 [528]

Answer:

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Step-by-step explanation:

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L=35cm

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