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olga_2 [115]
3 years ago
8

A sequence can be generated by using an=4a(n-1)

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0
This problem is half understanding the question and half just plugging in numbers.

Understanding the Question:
So its saying that n = whole number bigger than one, making n = 2, 3, 4, 5, etc.

Now try plugging any number n into the a_n = 4a_{n-1} equation. Let's use 2 to make it simple. If you plug in 2, you get:
a_2 = 4a_{2-1}\\
a_2 = 4a_1
Remember that the subscripts (the small numbers in the corner) are simply the term number. a_1 is term 1, a_2 is term 2, etc. The equation is saying that "term 2 = 4 times term 1."

If you keep plugging in random numbers for n, you'll see that the equation basically says, "a term = 4 times the term right before it." That makes it easy to plug and chug to get our answer.

Plugging and Chugging
Now we understand the question is asking for the first 4 terms, and each term is 4 times the last term. You're told that term 1, a_1 = 6. That makes the next four terms:

Term 2
a_2 = 4a_{2-1}\\
 a_2 = 4a_1\\
 a_2 = 4(6)\\
 a_2 = 24

Term 3
a_3 = 4a_{3-1}\\ a_3 = 4a_2\\ a_3 = 4(24)\\ a_3 = 96

Term 4
a_4 = 4a_{4-1}\\ a_4 = 4a_3\\ a_4 = 4(96)\\ a_4 = 384

Your first 4 terms are 4, 24, 96, and 384.

--------

Answer: A) F

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Hi

5/7 × 11/7 × 5/6 = 55/49 × 5/6 = 275/294

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Pls help trig question!!
s2008m [1.1K]

4\sin^2 x - 3 = 3 \sin x\\\\\implies 4\sin^2 x -3 \sin x  -3 =0\\\\\implies 4u^2 -3u -3 =0~~~~~~~~~~~~~~;[\text{Set} ~ \sin x = u]\\\\\implies u = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4\cdot 4 \cdot (-3)}}{2(4)}~~~~~~;[\text{Apply quadratic formula}]\\\\\\\implies u = \dfrac{3\pm\sqrt{57}}8\\\\\implies \sin x = \dfrac{3\pm\sqrt{57}}8~~~~~~;[\text{Substitute back}~ u = \sin x]\\\\\text{Now,}\\\\\sin x = \dfrac{3+\sqrt{57}}8\\\\\text{No solution for}~ x\in \mathbb{R}  ~\text{Since}~ -1\leq \sin x \leq 1\\

\sin x = \dfrac{3 - \sqrt{57}}8\\\\\implies x = n\pi + (-1)^n \sin^{-1} \left(\dfrac{3-\sqrt{57}}8\right)\\\\\\\text{ When n = 1,2 and}~  [0,2\pi]},\\\\\\x= \pi - \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)~ \text{and} ~x =  2\pi + \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)\\\\\text{In decimal,}\\\\x= 3.75~~~~ \text{and}~~~ x =5.68

5 0
2 years ago
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