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Arte-miy333 [17]
3 years ago
11

Factor the expression. 48g2 – 22gh – 15h2

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0
The answer is (6g-5h)(8g+3h)
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Given f(x) = x² - 10x + 22, what is the range of f?
adoni [48]

Answer:

[-3, ∞)

Step-by-step explanation:

There are many ways to find the range but I will use the method I find the easiest.

First, find the derivative of the function.

f(x) = x² - 10x + 22

f'(x) = 2x - 10

Once you find the derivative, set the derivative equal to 0.

2x - 10 = 0

Solve for x.

2x = 10

x = 5

Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.

f(x) = x² - 10x + 22

f(5) = 5² - 10(5) + 22

      = 25 - 50 +22

      = -3

Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.

This means the range is : [-3, ∞)

Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).

Hope this helped!

6 0
3 years ago
Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
Ursula Vanov can invest $5,000 in a 1-year CD at 3% compounded monthly or a 1-year CD compounded daily. Determine the amount at
Aliun [14]
Solving for the amount of maturity given that it is compounded monthly for 1 year with an interest of 3%, we have the formula and solution below:
A = P (1+r/n)^rn 
A = $5,000 (1.040417)
A =$5202.085

For compounded daily, we have the solution below:
A = $5,000 (1.040443)
A = $5202.215

The difference in amount is shown below:
Difference = $5202.215 - $5202.085
Difference = $0.13
7 0
3 years ago
Which of these statements is true?
zlopas [31]
Which Statements?


You didn't put any Statements there
8 0
4 years ago
Which point is on a line that passes through point R and is perpendicular to line PQ?
aliya0001 [1]
Your answer would be (-4,-8)
5 0
3 years ago
Read 2 more answers
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