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Ugo [173]
3 years ago
14

Write a number that is greater than 100, but smaller than 10,000. Divide that number by 10, 100, or 1,000 to get a number that i

s less than 100, but greater than 10
Mathematics
1 answer:
inn [45]3 years ago
4 0
Number: 550

Step by Step Explanation:
550 divided by 10 = 55
55 is less than 100, but greater than 10.
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What is 65/8 as a mixed number
Stolb23 [73]
List\ of\ the\ multiples\ of\ 8:0;\ 8;\ 126;\ 24;\ 32;\ 40;\ 48;\ 56;\ \boxed{64}\\\\\frac{65}{8}=\frac{64+1}{8}=\frac{64}{8}+\frac{1}{8}=\boxed{8\frac{1}{8}}
6 0
3 years ago
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Chin Woo bought a home for $160,000. He put down 20%. The mortgage is a 8 1/2% for 25 years. His yearly payments are?
PolarNik [594]
Amount of the mortgage after down payment is
160,000−160,000×0.2=128,000

Now use the formula of the present value of annuity ordinary to find the yearly payment
The formula is
Pv=pmt [(1-(1+r)^(-n))÷r]
Pv present value 128000
PMT yearly payment?
R interest rate 0.085
N time 25 years
Solve the formula for PMT
PMT=pv÷[(1-(1+r)^(-n))÷r]
PMT= 128,000÷((1−(1+0.085)^(
−25))÷(0.085))
=12,507.10 ....answer
6 0
3 years ago
Your friend works as a salesman in a shop were she earns $200 a week. She is paid a commission of 5% of her sales. How much did
Jet001 [13]
4500/100 = 45 x 5 = $225
6 0
4 years ago
The rectangle below has an area of x^2-144x
dangina [55]

Answer:

37x, 12

Step-by-step explanation:

8 0
4 years ago
The sum of three numbers is 12 . The sum of twice the first​ number, 3 times the second​ number, and 4 times the third number is
Harlamova29_29 [7]

Given:

The sum of three numbers is 12 .

The sum of twice the first​ number, 3 times the second​ number, and 4 times the third number is 37 .

The difference between 7 times the first number and the second number is 25.

To find:

The three number.

Solution:

Let the three numbers are x, y and z respectively.

According to the question,

x+y+z=12           ...(i)

2x+3y+4z=37         ...(ii)

7x-y=25           ...(iii)

From (iii), we get

-y=25-7x

y=-25+7x

Put y=-25+7x value in (i).

x+(-25+7x)+z=12

8x-25+z=12

8x+z=12+25

8x+z=37        ...(iv)

Put y=-25+7x value in (ii).

2x+3(-25+7x)+4z=37

2x-75+21x+4z=37

23x+4z=37+75

23x+4z=112          ...(v)

Now, Multiply equation (iv) by 4 and subtract the result from (v).

23x+4z-4(8x+z)=112-4(37)

23x+4z-32x-4z=112-148

-9x=-36

x=4

Put x=4 in (iv).

8(4)+z=37

32+z=37

z=37-32

z=5

Put x=4 in y=-25+7x.

y=-25+7(4)

y=-25+28

y=3

Therefore, the three numbers are 4, 3 and 5 respectively.

7 0
3 years ago
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