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ZanzabumX [31]
3 years ago
15

How many coefficients are in the expression 1/3y^2 - 18y + 9- 2y^-2

Mathematics
1 answer:
docker41 [41]3 years ago
4 0

There are four coefficients in that expression, so the coefficients are 1/3, -18, 9, and -2.

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Mrrafil [7]

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Step-by-step explanation:

Given polynomials are:

(x^3+3x^2+1)\\and\\(3x^2+6x-2)

In order to multiply both polynomials, we will use the distributive property

So,

= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2

Combining like terms

=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2

Hence,

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Keywords: Polynomials, variables

Learn more about polynomials at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

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