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3 years ago

How many coefficients are in the expression 1/3y^2 - 18y + 9- 2y^-2

Mathematics

1 answer:

docker41 [41]3 years ago

4 0

There are four coefficients in that expression, so the coefficients are 1/3, -18, 9, and -2.

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(NEED HELP ASAP!!!) Jamie unfolded a cardboard box. The figure of the unfolded box is shown below: A long rectangle divided alon

Oksanka [162]

Answer:

6 x 4 x 4 Hope I get u right<3

Step-by-step explanation:

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3 years ago

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3 years ago

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tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

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Irina18 [472]

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Step-by-step explanation:

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2 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

3 years ago